1 / 6

V 1

Modeling of Electrical Circuits. C. L. +. V 1. -. R 1. R 2. Q q. Q q2. Current in the resistor R 1 =. q ve q 2 : Gen. charges. Example 3.1:. V 1 : Input. L=3.4 mH, C=286 µ F, R 1 =3.2 Ω , R 2 =4.5 Ω. D(s)=0.02618s 3 +26.288s 2 +11188.81s=0.

marsha
Télécharger la présentation

V 1

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript

  1. Modeling of Electrical Circuits C L + V1 - R1 R2 Qq Qq2 Current in the resistor R1 = q ve q2 : Gen. charges Example 3.1: V1: Input L=3.4 mH, C=286 µF, R1=3.2 Ω, R2=4.5 Ω D(s)=0.02618s3+26.288s2+11188.81s=0 Eigenvalues: 0, -502.06±418.70i (ξ=0.768)

  2. In op-amp input, resistance is too high C1 R3 C2 R1 V1 V2 R2 - + Example3.2 Input :V1 Generalized charges: q1, q2, q3 Also, in op-amp: V+=V-=0

  3. R1=15.9 kΩ, R2=837 Ω, R3=318 kΩ, C1=C2=0.005 µF Eigenvalues: 0, -628.93±12561.76i (ξ=0.05)

  4. C R2 R R1 V2 V2 V1 V1 V1 R - - - C + + + V2

  5. R R R R R R R R R V3 V2 V1 Vc - - V1 - + + + Vc + V1 - Vc V2 V2

  6. C3 R2 R3 R1 R R R R4 - - - V1 R + + + C4 V2 - + PID control circuit

More Related