1 / 11

Physics of a Roller Coaster: Speeds and Deceleration Analysis

This analysis explores the physics of a roller coaster navigating a hill and a loop. Part A calculates the speed at the bottom of a 20m hill, utilizing energy conservation principles. Part B determines the speed at the top of a 15m loop, incorporating gravitational and kinetic energy equations. Finally, part C examines the deceleration caused by drag when the coaster runs on a flat track in a frictionless scenario. The calculations reflect fundamental physics concepts while considering real-world factors like air density and drag coefficient.

matthew-trujillo
Télécharger la présentation

Physics of a Roller Coaster: Speeds and Deceleration Analysis

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript

  1. CORKSCREW

  2. QUESTION: The roller coaster is at the top of the hill 20m high and moving at a speed of 10m/sec.

  3. a) (assume no friction) How fast will the coaster be moving at the bottom of the hill before going into the loop?

  4. b) (assume no friction) How fast will the roller coaster be moving at the top of a loop which is 15m high?

  5. The density of air is 1.75 kg/m3, the area of the coaster is 4m2, and the drag coefficient for the coaster is 0.8.

  6. c) (in a perfect physics world) If the wind starts up after going out of the loop; a drag force is created to stop the coaster. Find the deceleration of the coaster if the coaster is running on a flat track.

  7. Find the deceleration of the coaster starting here!

  8. ANSWERS

  9. A Since gravitational potential energy is 0 at the bottom; PE and mass cancels out. ½v2 = ½v2 250 = ½v2 2 x 250 = v2 √500 = v 22.36 = v

  10. B PE + KE = PE + KE Mgh + 1/2mv2 = mgh + 1/2mv2 (9.8)(20) + ½(10)2 = (9.8)(15) + ½ v2 196 + 50 = 147 + ½ v2 2(246-147) = v2 √198 = v 14.07 = v

  11. CFd = ma½pv2CdA = ma ½(1.75)(22.36)2(0.8)(4) = 400a1399.91488 = 400a1399.91488/400 = a3.50 m/s2 = a

More Related