1 / 8

Using formulas to solve problems lesson 1-6

Using formulas to solve problems lesson 1-6. Lesson essential Questions. What is the purpose of a formula? How can formulas be used to find the area of irregular objects?. Formula-an equation that tells you how one variable is related to one or more other variables.

mira
Télécharger la présentation

Using formulas to solve problems lesson 1-6

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript

  1. Using formulas to solve problemslesson 1-6

  2. Lesson essential Questions What is the purpose of a formula? How can formulas be used to find the area of irregular objects?

  3. Formula-an equation that tells you how one variable is related to one or more other variables.

  4. Square area = a² Trapezoid area = h(b + b) ÷ 2 Parallelogram area = bh Triangle area + bh ÷ 2 Rectangle area = bh

  5. Solve formula problems • Write the formula needed to solve the problem • Substitute the values for the variables • Follow order of operations • Parentheses • Exponents • Multiply and divide left to right • Add and subtract left to right

  6. Find the area of a rectangle that has a width of 15 inches and a height of 10 inches. area of a rectangle = base (height) area = bh area = 15 inches (10 inches) area = 150 square inches or 150 in²

  7. Use the formula A= h(b+b)÷2 The height is 44 miles and the bases or 45 miles and 16 miles. Find the area of the trapezoid.

  8. area of a trapezoid = h(b + b)÷ 2 Area = 44 miles(45 miles + 16 miles)÷2 Area = 44 miles(720 miles²)÷ 2 Area = 31680 miles² ÷ 2 Area = 15840 miles²

More Related