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OB: Stoich3, Plotting the problems, then doing them right.

OB: Stoich3, Plotting the problems, then doing them right. First, get out your maps, and your periodic tables, and a calculator. Let’s look at the map here…. vol. vol. Mole ratio tunnel. moles. moles. # of particles. mass. # of particles. mass.

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OB: Stoich3, Plotting the problems, then doing them right.

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  1. OB: Stoich3, Plotting the problems, then doing them right. First, get out your maps, and your periodic tables, and a calculator. Let’s look at the map here… vol vol Mole ratio tunnel moles moles # of particles mass # of particles mass

  2. Problem 1, YOU have 4.56 x 1025 atoms of zinc that you wan to put into hydrochloric acid to make them fizz away. How many grams of hydrogen gas form? Don’t do this, let’s talk about where to start, where to go next, and balance this equation. vol vol Mole ratio tunnel moles moles # of particles mass # of particles mass

  3. Problem 2, YOU want to know how many molecules of water form when 55.3 Liters of methane combust. Balance the equation, show the plan of attack on the map. vol vol Mole ratio tunnel moles moles # of particles mass # of particles mass

  4. Problem 3, YOU need (sorry, it’s true) to know how many liters of nitrogen gas are required to combine with 809 liters of hydrogen when ammonia forms. Balance the equation, show the plan on the map, but don’t do this problem. vol vol Mole ratio tunnel moles moles # of particles mass # of particles mass

  5. Problem 1, YOU have 4.56 x 1025 atoms of zinc that you wan to put into hydrochloric acid to make them fizz away. How many grams of hydrogen gas form? Do this now. Zn + 2HCl(AQ) ZnCl2 + H2 Mole ratio tunnel moles moles # of particles mass

  6. Problem 1, YOU have 4.56 x 1025 atoms of zinc that you wan to put into hydrochloric acid to make them fizz away. How many grams of hydrogen gas form? Do this now. Zn + 2HCl(AQ) ZnCl2 + H2 1. 4.56 x 1025 atoms 1 1 mole Zn6.02 x 1023 atoms Zn 4.566.02 10251023 x = x 75.7 moles Zn = ZnH2 11 75.7X 2. MR X = 75.7 moles hydrogen 2 grams H21 mole H2 3. 75.7 moles H2 1 x 151 grams H2 = Mole ratio tunnel moles moles # of particles mass

  7. Problem 2, YOU want to know how many molecules of water form when 55.3 Liters of methane combust. Do this now. CH4 + 2O2 CO2 + 2H2O vol Mole ratio tunnel moles moles # of particles

  8. Problem 2, YOU want to know how many molecules of water form when 55.3 Liters of methane combust. Do this now. CH4 + 2O2 CO2 + 2H2O 1 mole methane22.4 Liters CH4 1.55.3 L CH41 x = 2.47 moles methane MethaneWater 12 2.47X X = 4.94 moles of water 2. MR 6.02 x 1023 molecules1 mole water 3. 4.94 moles water1 29.7388 x 1023 molecules 2.97 x 1024 moleculesof water x = vol Mole ratio tunnel moles moles # of particles

  9. Problem 3, YOU need (sorry, it’s true) to know how many liters of nitrogen gas are required to combine with 809 liters of hydrogen when ammonia forms. 3H2 + N2 2NH3 vol vol Mole ratio tunnel moles moles

  10. Problem 3, YOU need (sorry, it’s true) to know how many liters of nitrogen gas are required to combine with 809 liters of hydrogen when ammonia forms. 3H2 + N2 2NH3 1. 809 L H2 1 1 mole nitrogen22.4 L H2 x = 36.1 moles H2 nitrogenhydrogen 13 X36.1 3X = 36.1 moles X = 12.0 moles nitrogen 2. MR 22.4 L N21 mole N2 3. 12.0 moles N2 1 x = 269 Liters hydrogen gas vol vol Mole ratio tunnel moles moles

  11. Stoich HW #3 due Tuesday Dec 13: review of stoich then Stoich Celebration of KnowledgeWEDNESDAY There are four sets of questions about 4 different reactions. You must determine the type of reaction, the mole ratio, and then 3 questions about the reaction. One will be moles to moles, the others will be3-step stoich problems. You will choose only 2 sets to do, your choice. Reactions lab is late, so is the MgO Lab. Stoich HW 1 + 3 are late Stoich 2 Lab Due NOW.

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