1 / 12

Solutions and Concentrations

Solutions and Concentrations. Notes Page 5. SOLUTIONS . A homogenous mixture of two or more substances. 2 PARTS OF A SOLUTION. SOLUTE A solute is the dissolved substance in a solution. Sugar in soda Carbon dioxide in soda Salt in salt water SOLVENT

mura
Télécharger la présentation

Solutions and Concentrations

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript


  1. Solutions and Concentrations Notes Page 5

  2. SOLUTIONS A homogenous mixture of two or more substances

  3. 2 PARTS OF A SOLUTION • SOLUTE • A solute is the dissolved substance in a solution. Sugar in soda Carbon dioxide in soda Salt in salt water • SOLVENT • A solvent is the dissolving medium in a solution. • Water in salt water Waterin soda

  4. Molarity = concentration • Amount of substance (mol) • Volume of mixture (L) • Unit = mol/L or M • 1.0 M = 1 molar • 12.0 M = 12 molar

  5. solUTE over solVENT

  6. Example 1 • 1.5 mol of NaCl are dissolved in 1 L of water. What is the molarity of the solution? • 1.5 molNaCl= 1.5 mol/L or 1.5 M • 1 L H2O

  7. Example 2 • 100 g of NaCl are dissolved in 1 L of water. What is the molarity of the solution? • 100 g NaCl|1 molNaCl= 1.71 mol 58.44 g NaCl • 1.71 molNaCl= 1.71 M 1 L

  8. Example 3 • 100 g of NaCl are dissolved in 250 mL of water. What is the molarity of the solution? • 100 g NaCl |1 molNaCl= 1.71mol • 58.44 g NaCl • 250 mL / 103 mL = 0.25 L • 1.71 molNaCl= 6.84 M 0.25 L

  9. Example 4 • How many moles of NaCl are in 500 mL of a 0.25 M solution? • Basic formula: M = mol L • Convert: 500 mL = 0.5 L • 0.25 M = mol = 0.5 L x 0.25 M = mol 0.5 L = 0.125 molNaCl

  10. Example 5 • How many grams of NaClare in 500 mL of a 2.25 M solution? • Basic formula: M = mol L • Convert: 500 mL = 0.5 L • 2.25 M = mol = 0.5 L x 2.25 M = mol 0.5 L= 1.125 molNaCl • 1.125 molNaCl| 58.44 g NaCl= 65.75 g NaCl 1 mol

More Related