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Basic Stoichiometry Problems

Basic Stoichiometry Problems. Please use these examples to solve today’s problems. Example #1. If 35.80g of aluminum chloride reacts with excess silver nitrate, how many grams of the ppt will be formed? 1 AlCl 3(aq) + 3AgNO 3(aq) Al(NO 3 ) 3(aq) + 3 AgCl (s)

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Basic Stoichiometry Problems

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  1. Basic Stoichiometry Problems Please use these examples to solve today’s problems

  2. Example #1 If 35.80g of aluminum chloride reacts with excess silver nitrate, how many grams of the ppt will be formed? 1AlCl3(aq) + 3AgNO3(aq) Al(NO3)3(aq) + 3AgCl(s) 35.80g AlCl3 1mol AlCl33mol AgCl 143.32g AgCl 132.76g AlCl31mol AlCl3 1mol AgCl = 115.9g AgCl

  3. Example #2 15.0ml of a 3.0M magnesium chloride solution reacts with excess silver nitrate, how many grams of ppt will be formed? 1 MgCl2(aq) + 2 AgNO3(aq) Mg(NO3)2(aq) + 2AgCl(s) 15.0ml 1 Liter 3.0 mole MgCl22mol AgCl 143.32g AgCl 1000l 1 liter 1mol MgCl2 1mol AgCl = 12.9g AgCl

  4. Example #3 12.01g of ammonium carbonate reacts with excess ferrous bromide. How many grams of the ppt will be formed? 1(NH4)2CO3(aq) + FeBr2(aq) 2NH4Br(aq) + 1FeCO3 (s) 12.01g(NH4)2CO3 1mol (NH4)2CO31mol FeCO3 115.86g 96.11g 1mol (NH4)2CO3 1mol FeCO3 = 14.48g FeCO3

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