1 / 19

Rotational Equations and Center of Mass

Rotational Equations and Center of Mass. Use one of the rotational constant acceleration equations. You have a wheel that starts at 10 rad/s. It accelerates with a rotational acceleration of -0.5  rad/s 2 . What is the magnitude of its angular displacement after 20 s?.

Télécharger la présentation

Rotational Equations and Center of Mass

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript


  1. Rotational Equations and Center of Mass

  2. Use one of the rotational constant acceleration equations. You have a wheel that starts at 10 rad/s. It accelerates with a rotational acceleration of -0.5  rad/s2. What is the magnitude of its angular displacement after 20 s?

  3. You see four cars from an airplane. Being bored you derive an equation for each of their positions. The first is x(t) = 2t+5. The second is x(t) = -6t-4. The third is y(t) = 4t. The fourth is x(t) = -4 and y(t) = 7t+5. At time t = 0, what is the center of mass of the four car system?

  4. You see four cars from an airplane. Being bored you derive an equation for each of their positions. The first is x(t) = 2t+5. The second is x(t) = -6t-4. The third is y(t) = 4t. The fourth is x(t) = -4 and y(t) = 7t+5. At time t = 2, what is the center of mass of the four car system?

  5. You see four cars from an airplane. Being bored you derive an equation for each of their positions. The first is x(t) = 2t+5. The second is x(t) = -6t-4. The third is y(t) = 4t. The fourth is x(t) = -4 and y(t) = 7t+5. What is the speed of the center of the mass of this system?

  6. A pole has a linear density of (0.3 x) kg/m. If it has a length of 200 cm, where is the center of mass from the lighter end of the bat?

  7. Which of the following is the rotational counterpart of force? • q • w • a • I • t • K • L

  8. What is the name of the variable t? • Angular Acceleration • Moment of Inertia • Torque • Rotational Kinetic Energy • Angular Momentum • Angular displacement (angle) • Angular velocity • Angular Force

  9. What is the magnitude of the force that the ball is putting on the cross-beam? y x m = 200 kg

  10. Given the board below and using the equation and assuming that the point of rotation is the one shown, what is the magnitude of the torque that the ball is putting on the cross-beam? y Point of rotation x 30o 10 m m = 200 kg

  11. Given the board below and using the equation and assuming that • the point of rotation is the one shown, what is the direction of the torque • that the ball is putting on the cross-beam? • i 3. j 5. k • -i 4. -j 6. -k y Point of rotation x 30o 10 m m = 200 kg

  12. What keeps the truck from flipping over? • The tension in the cable • The weight of the of the truck • The torque from the cable • The torque from the weight of the truck y Point of rotation x 30o 10 m m = 200 kg

  13. What is the magnitude of the torque from the weight of the truck? y Point of rotation x 30o 10 m m = 200 kg

  14. What is the direction of the torque from the weight of the truck? • i 3. j 5. k • -i 4. -j 6. -k y Point of rotation x 30o 10 m m = 200 kg

  15. If the truck weight 2000 kg, how far is the center of mass of the truck from the center of rotation? y Point of rotation x 30o 10 m m = 200 kg

  16. Adding 100 kg to the mass of the ball, we change the total torque. If the entire truck rotates with an acceleration of 5 rad/s2, what is its moment of inertia? y Point of rotation x 30o 10 m m = 200 kg

  17. Using the moment of inertia from the last question and the angular acceleration of 5 rad/s2, what is the magnitude of the angular momentum of the truck after 10 seconds? y Point of rotation x 30o 10 m m = 200 kg

  18. Using the moment of inertia from the last question and the angular acceleration of 5 rad/s2, what is the rotational kinetic energy of the truck after 10 seconds? y Point of rotation x 30o 10 m m = 200 kg

  19. A spinning cue ball hits the eight ball in a game of billiards. Which of the following quantities are conserved? • Translational Velocity • Translational Momentum • Force • Translational Kinetic Energy • Angular Velocity • Angular Momentum • Torque • Rotational Kinetic Energy

More Related