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This lecture explores the characteristics of narrow-base diodes, focusing on the impact of minority carrier diffusion lengths on current behavior in pn junctions. We derive the diode I-V equation under specific boundary conditions, emphasizing how excess carrier concentrations are affected in one-sided junctions. Additionally, the lecture discusses breakdown mechanisms, including avalanche and tunneling breakdown, detailing how dopant concentration and electric fields influence breakdown voltages. The insights provided are crucial for modern semiconductor applications in integrated circuits.
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Lecture 11 OUTLINE • pn Junction Diodes (cont’d) • Narrow-base diode • Junction breakdown Reading: Pierret 6.3.2, 6.2.2; Hu 4.5
Introduction • The ideal diode equation was derived assuming that the lengths of the quasi-neutral p-type & n-type regions (WP’ , WN’) are much greater than the minority-carrier diffusion lengths (Ln , Lp) in these regions. • Excess carrier concentrations decay exponentially to 0. • Minority carrier diffusion currents decay exponentially to 0. • In modern IC devices, however, it is common for one side of a pn junction to be shorter than the minority-carrier diffusion length, so that a significant fraction of the “injected” minority carriers reach the end of the quasi-neutral region, at the metal contact. Recall that Dp = Dn = 0 at an ohmic contact In this lecture we re-derive the diode I-V equation with the boundary condition that Dp = 0 at a distance xc’ (rather than ) from the edge of the depletion region. EE130/230A Fall 2013 Lecture 11, Slide 2
Excess Carrier Distribution (n side) • From the minority carrier diffusion equation: • For convenience, let’s use the coordinate system: • So the solution is of the form: • We have the following boundary conditions: x’’ 0 0 x’ xc' EE130/230A Fall 2013 Lecture 11, Slide 3
Applying the boundary conditions, we have: Therefore Since this can be rewritten as We need to take the derivative of Dpn’ to obtain the hole diffusion current within the quasi-neutral n region: EE130/230A Fall 2013 Lecture 11, Slide 4
Thus, for a one-sided p+n junction (in which the current is dominated by injection of holes into the n-side) with a short n-side: Evaluate Jp at x=xn (x’=0) to find the injected hole current: EE130/230A Fall 2013 Lecture 11, Slide 5
and Therefore if xc’ << LP: For a one-sided p+n junction, then: EE130/230A Fall 2013 Lecture 11, Slide 6
Excess Hole Concentration Profile If xc’ << LP: Dpn is a linear function: • Jp is constant (No holes are lost due to recombination as they diffuse to the metal contact.) Dpn(x) slope is constant x' 0 x'c 0 EE130/230A Fall 2013 Lecture 11, Slide 7
General Narrow-Base Diode I-V • Define WP‘ and WN’ to be the widths of the quasi-neutral regions. • If both sides of a pn junction are narrow (i.e. much shorter than the minority carrier diffusion lengths in the respective regions): e.g. if hole injection into the n side is greater than electron injection into the p side: J JP JN x xn -xp EE130/230A Fall 2013 Lecture 11, Slide 8
Summary: Narrow-Base Diode • If the length of the quasi-neutral region is much shorter than the minority-carrier diffusion length, then there will be negligible recombination within the quasi-neutral region and hence all of the injected minority carriers will “survive” to reach the metal contact. • The excess carrier concentration is a linear function of distance. For example, within a narrow n-type quasi-neutral region: • The minority-carrier diffusion current is constant within the narrow quasi-neutral region. Shorter quasi-neutral region steeper concentration gradient higher diffusion current Dpn(x) location of metal contact (Dpn=0) x 0 xn WN’ EE130/230A Fall 2013 Lecture 11, Slide 9
pn Junction Breakdown C. C. Hu, Modern Semiconductor Devices for Integrated Circuits, Figure 4-10 Breakdown voltage, VBR VA AZener diodeis designed to operate in the breakdown mode: EE130/230A Fall 2013 Lecture 11, Slide 10
Review: Peak E-Field in a pn Junction E(x) -xp xn x E(0) For a one-sided junction, where N is the dopant concentration on the lightly doped side EE130/230A Fall 2013 Lecture 11, Slide 11
Breakdown Voltage, VBR • If the reverse bias voltage (-VA) is so large that the peak electric field exceeds a critical value ECR, then the junction will “break down” (i.e. large reverse current will flow) • Thus, the reverse bias at which breakdown occurs is EE130/230A Fall 2013 Lecture 11, Slide 12
Avalanche Breakdown Mechanism R. F. Pierret, Semiconductor Device Fundamentals, Figure 6.12 High E-field: if VBR >> Vbi Low E-field: • ECR increases slightly with N: • For 1014 cm-3 < N < 1018 cm-3, • 105 V/cm < ECR < 106 V/cm EE130/230A Fall 2013 Lecture 11, Slide 13
Tunneling (Zener) Breakdown Mechanism Dominant breakdown mechanism when both sides of a junction are very heavily doped. VA = 0 VA < 0 Ec Ev Typically, VBR < 5 V for Zener breakdown C. C. Hu, Modern Semiconductor Devices for Integrated Circuits, Figure 4-12 EE130/230A Fall 2013 Lecture 11, Slide 14
Empirical Observations of VBR R. F. Pierret, Semiconductor Device Fundamentals, Figure 6.11 • VBR decreases with increasing N • VBR decreases with decreasing EG EE130/230A Fall 2013 Lecture 11, Slide 15
VBR Temperature Dependence • For the avalanche mechanism: • VBR increases with increasing T, because the mean free path decreases • For the tunneling mechanism: • VBRdecreases with increasing T, because the flux of valence-band electrons available for tunneling increases EE130/230A Fall 2013 Lecture 11, Slide 16
Summary: Junction Breakdown • If the peak electric field in the depletion region exceeds a critical value ECR, then large reverse current will flow. This occurs at a negative bias voltage called the breakdown voltage, VBR: where N is the dopant concentration on the more lightly doped side • The dominant breakdown mechanism is avalanche, if N < ~1018/cm3 tunneling, if N > ~1018/cm3 EE130/230A Fall 2013 Lecture 11, Slide 17