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Do Now: p.528, #27

Do Now: p.528, #27. Find the measures of the angles of the triangle whose vertices are A = (–1, 0), B = (2, 1), and C = (1, –2). Component forms:. Magnitudes:. Do Now: p.528, #27. Find the measures of the angles of the triangle whose vertices are A = (–1, 0), B = (2, 1), and C = (1, –2).

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Do Now: p.528, #27

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  1. Do Now: p.528, #27 Find the measures of the angles of the triangle whose vertices are A = (–1, 0), B = (2, 1), and C = (1, –2). Component forms: Magnitudes:

  2. Do Now: p.528, #27 Find the measures of the angles of the triangle whose vertices are A = (–1, 0), B = (2, 1), and C = (1, –2). Angle at A:

  3. Do Now: p.528, #27 Find the measures of the angles of the triangle whose vertices are A = (–1, 0), B = (2, 1), and C = (1, –2). Angle at B:

  4. Do Now: p.528, #27 Find the measures of the angles of the triangle whose vertices are A = (–1, 0), B = (2, 1), and C = (1, –2). Angle at C:

  5. Vector Applications Section 10.2b

  6. Suppose the motion of a particle in a plane is represented by parametric equations. The tangent line, suitably directed, models the direction of the motion at the point of tangency. y A vector is tangent or normal to a curve at a point P if it is parallel or normal, respectively, to the line that is tangent to the curve at P. x

  7. Finding Vectors Tangent and Normal to a Curve Find unit vectors tangent and normal to the parametrized curve at the point where . Coordinates of the point: A graph of what we seek: y n u –u –n x

  8. Finding Vectors Tangent and Normal to a Curve Find unit vectors tangent and normal to the parametrized curve at the point where . Tangent slope: A basic vector with a slope of 1/2: To find the unit vector, divide v by its magnitude:

  9. Finding Vectors Tangent and Normal to a Curve Find unit vectors tangent and normal to the parametrized curve at the point where . The other unit vector: To find the normal vectors (with opposite reciprocal slopes), interchange components and change one of the signs:

  10. Finding Ground Speed and Direction An airplane, flying due east at 500 mph in still air, encounters a 70-mph tail wind acting in the direction north of east. The airplane holds its compass heading due east but, because of the wind, acquires a new ground speed and direction. What are they? Let a = airplane velocity and w = wind velocity. N We need the magnitude of the resultant a + w and the measure of angle theta. w a + w E a

  11. Finding Ground Speed and Direction An airplane, flying due east at 500 mph in still air, encounters a 70-mph tail wind acting in the direction north of east. The airplane holds its compass heading due east but, because of the wind, acquires a new ground speed and direction. What are they? Component forms of the vectors: The resultant: Magnitude:

  12. Finding Ground Speed and Direction An airplane, flying due east at 500 mph in still air, encounters a 70-mph tail wind acting in the direction north of east. The airplane holds its compass heading due east but, because of the wind, acquires a new ground speed and direction. What are they? Direction angle: N w a + w E a The new ground speed of the airplane is approximately 538.424 mph, and its new direction is about 6.465 degrees north of east.

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