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This document discusses fundamental physics calculations involving acceleration, force, and mass. It highlights how to determine the acceleration of a boy given a force of 15 N and a mass of 58 kg, yielding an acceleration of 0.26 m/s². It also explores the force required to accelerate a 1250 kg car at 40 m/s², calculated to be 50,000 N. Finally, it addresses the calculation of mass when a force of 34 N produces an acceleration of 4 m/s², resulting in a mass of 8.5 kg. These examples illustrate the application of Newton's laws of motion.
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Q 4, 5, 6 p351 Acceleration of boy if force = 15 N (fwd) & mass = 58 kg?DON’T KNOW: a = ?KNOW: F = 15 N, m = 58 kgFORMULA: a = F/m = 15 N (fwd) / 58 kg = 0.26 m/s2 (fwd) Force needed to accelerate 1250 kg car at 40 m/s2 (fwd) ?DK: F = ?K: m = 1250 kg, a = 40 m/s2 (fwd)FORMULA: F = ma = 1250 kg * 40 m/s2 (fwd) = 50,000 N What is mass of object if force of 34 N (fwd) produces acceleration of 4 m/s2 (fwd)?DK: m = ?K: F = 34 N (fwd), a = 4 m/s2 (fwd)FORMULA: m = F/a = 34 N / 4 m/s2 = 8.5 kg 6 pts: 2 pts ea
Q 4, 5, 6 p351 Acceleration of boy if force = 15 N (fwd) & mass = 58 kg?DON’T KNOW: a = ?KNOW: F = 15 N, m = 58 kgFORMULA: a = F / m = 15 N (fwd) / 58 kg = 0.26 m/s2 (fwd) Force needed to accelerate 1250 kg car at 40 m/s2 (fwd) ?DK: F = ?K: m = 1250 kg, a = 40 m/s2 (fwd)FORMULA: F = ma = 1250 kg * 40 m/s2 (fwd) = 50,000 N What is mass of object if force of 34 N (fwd) produces acceleration of 4 m/s2 (fwd)?DK: m = ?K: F = 34 N (fwd), a = 4 m/s2 (fwd)FORMULA: m = F/a = 34 N / 4 m/s2 = 8.5 kg 6 pts: 2 pts ea
Q 4, 5, 6 p351 Acceleration of boy if force = 15 N (fwd) & mass = 58 kg?DON’T KNOW: a = ?KNOW: F = 15 N, m = 58 kgFORMULA: a = F / m = 15 N (fwd) / 58 kg = 0.26 m/s2 (fwd) Force needed to accelerate 1250 kg car at 40 m/s2 (fwd) ?DK: F = ?K: m = 1250 kg, a = 40 m/s2 (fwd)FORMULA: F = m • a = 1250 kg • 40 m/s2 (fwd) = 50,000 N What is mass of object if force of 34 N (fwd) produces acceleration of 4 m/s2 (fwd)?DK: m = ?K: F = 34 N (fwd), a = 4 m/s2 (fwd)FORMULA: m = F/a = 34 N / 4 m/s2 = 8.5 kg 6 pts: 2 pts ea
Q 4, 5, 6 p351 Acceleration of boy if force = 15 N (fwd) & mass = 58 kg?DON’T KNOW: a = ?KNOW: F = 15 N, m = 58 kgFORMULA: a = F / m = 15 N (fwd) / 58 kg = 0.26 m/s2 (fwd) Force needed to accelerate 1250 kg car at 40 m/s2 (fwd) ?DK: F = ?K: m = 1250 kg, a = 40 m/s2 (fwd)FORMULA: F = m • a = 1250 kg • 40 m/s2 (fwd) = 50,000 N What is mass of object if force of 34 N (fwd) produces acceleration of 4 m/s2 (fwd)?DK: m = ?K: F = 34 N (fwd), a = 4 m/s2 (fwd)FORMULA: m = F / a = 34 N / 4 m/s2 = 8.5 kg 6 pts: 2 pts ea