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Chapter 30 Sources of magnetic field

Chapter 30 Sources of magnetic field. § 30-1 Field due to a long, straight wire. for infinite wire.  0 = 4  10 7. I 1 = 3A, I 2 = 5A, tan  =   = 53 0. Example 30.1. =1. 5  10  5 T; B 2 =2  10  5 T. B 1 =. B X = B 2 cos  =1.2  10  5 T.

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Chapter 30 Sources of magnetic field

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  1. Chapter 30 Sources of magnetic field §30-1 Field due to a long, straight wire for infinite wire 0 = 4107 I1 = 3A, I2 = 5A, tan =  = 530 Example 30.1 =1. 5105T; B2 =2105T B1= BX = B2cos=1.2105T BY = B1B2sin= 106T 106T

  2. §30-2 Magnetic force between parallel wires force per unit length (Definition of 1A) §30-3 Biot-Savart law for a current element 必歐沙瓦定律 Biot-Savart law

  3. 無限長導線 Example 30.2 infinite straight wire 2 1 r = = a csc x =  a cot  dx = a csc2 d 積分變數換成θ for a infinite long 1=0, 2=  B = 電流線圈 Example : Field of a current loop = 0 for OA and OC

  4. 圓線圈 Example 30.3 Circular loop ; By symmetry X = 0  B = X »R  B  (where  = IA = I  R2) (note : for a electric dipole E = )

  5. 螺線管 Example 30.4 A solenoid of length and radius R had N turns of wires and carries a current I .Find the field strength at a point along the axis.  of turns per unit length dI=nIdx x = R tan dx=R sec2 d If the solenoid is infinite, 1=900, 2= 900

  6. At the end of a very long solenoid , 1= 900, 2= 00 安培定律 §30-4 Ampere’s law (Biot-Savart law) Ampere‘s law The is due to all currents in the vicinity,not just the current enclosed by the path)  Geometry of the current flow possess sufficient symmetry  suitable choice for the path of integration.

  7. 半徑R之無限長導線 Example 30.5 An infinite straight wire of radius R carries I (i) r > R By symmetry (ii) r < R

  8. 理想無限長螺管 單位長度線圈密度 Example 30.6 An ideal infinite solenoid Example 30.7 A toroidal coil 總線圈數 環型螺管 r Ideal toroidal coil, B=0 outside of the coil

  9. 點電荷造成磁場 Example 30.8 Magnetic field produced by a point charge moving atvelocityV d

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