1 / 29

Chapter 6 Rational Expressions, Functions, and Equations

Chapter 6 Rational Expressions, Functions, and Equations. § 6.1. Rational Expressions and Functions: Multiplying and Dividing. Rational Expressions. A rational expression consists of a polynomial divided by a nonzero polynomial (denominator cannot be equal to 0).

ouida
Télécharger la présentation

Chapter 6 Rational Expressions, Functions, and Equations

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript

  1. Chapter 6Rational Expressions, Functions, and Equations

  2. §6.1 Rational Expressions and Functions: Multiplying and Dividing

  3. Rational Expressions A rational expression consists of a polynomial divided by a nonzero polynomial (denominator cannot be equal to 0). A rational function is a function defined by a formula that is a rational expression. For example, the following is a rational function: Blitzer, Intermediate Algebra, 5e – Slide #3 Section 6.1

  4. Rational Expressions EXAMPLE The rational function models the cost, f(x) in millions of dollars, to inoculate x% of the population against a particular strain of flu. The graph of the rational function is shown. Use the function’s equation to solve the following problem. Find and interpret f(60). Identify your solution as a point on the graph. p 393 Blitzer, Intermediate Algebra, 5e – Slide #4 Section 6.1

  5. Rational Expressions CONTINUED Blitzer, Intermediate Algebra, 5e – Slide #5 Section 6.1

  6. Rational Expressions CONTINUED SOLUTION We use substitution to evaluate a rational function, just as we did to evaluate other functions in Chapter 2. This is the given rational function. Replace each occurrence of x with 60. Perform the indicated operations. Blitzer, Intermediate Algebra, 5e – Slide #6 Section 6.1

  7. Rational Expressions CONTINUED Thus, f(60) = 195. This means that the cost to inoculate 60% of the population against a particular strain of the flu is $195 million. The figure below illustrates the solution by the point (60,195) on the graph of the rational function. (60,195) Blitzer, Intermediate Algebra, 5e – Slide #7 Section 6.1

  8. Rational Expressions - Domain EXAMPLE Find the domain of f if SOLUTION The domain of f is the set of all real numbers except those for which the denominator is zero. We can identify such numbers by setting the denominator equal to zero and solving for x. Set the denominator equal to 0. Factor. p 393 Blitzer, Intermediate Algebra, 5e – Slide #8 Section 6.1

  9. Rational Expressions - Domain CONTINUED or Set each factor equal to 0. Solve the resulting equations. Because 4 and 9 make the denominator zero, these are the values to exclude. Thus, or Blitzer, Intermediate Algebra, 5e – Slide #9 Section 6.1

  10. Rational Expressions - Domain CONTINUED In this example, we excluded 4 and 9 from the domain. Unlike the graph of a polynomial which is continuous, this graph has two breaks in it – one at each of the excluded values. Since x cannot be 4 or 9, there is not a function value corresponding to either of those x values. At 4 and at 9, there will be dashed vertical lines called vertical asymptotes. The graph of the function will approach these vertical lines on each side as the x values draw closer and closer to each of them, but will not touch (cross) the vertical lines. The lines x = 4 and x = 9 each represent vertical asymptotes for this particular function. p 395 Blitzer, Intermediate Algebra, 5e – Slide #10 Section 6.1

  11. Rational Expressions p 395 Blitzer, Intermediate Algebra, 5e – Slide #11 Section 6.1

  12. Rational Expressions - Domain Check Point 2 Find the domain of f if SOLUTION Set the denominator equal to 0. Factor. or Set each factor equal to 0. Solve the resulting equations. or p 394 Blitzer, Intermediate Algebra, 5e – Slide #12 Section 6.1

  13. Simplifying Rational Expressions EXAMPLE Simplify: SOLUTION Factor the numerator and denominator. Divide out the common factor, x + 1. Simplify. Blitzer, Intermediate Algebra, 5e – Slide #13 Section 6.1

  14. Simplifying Rational Expressions Check Point 3 Simplify: SOLUTION Factor the numerator and denominator. Divide out the common factor, x + 1. Simplify. p 397 Blitzer, Intermediate Algebra, 5e – Slide #14 Section 6.1

  15. Simplifying Rational Expressions EXAMPLE Simplify: SOLUTION Factor the numerator and denominator. Rewrite 3 – x as (-1)(-3 + x). Rewrite -3 + x as x – 3. Blitzer, Intermediate Algebra, 5e – Slide #15 Section 6.1

  16. Simplifying Rational Expressions CONTINUED Divide out the common factor, x – 3. Simplify. Do Check 4a and 4b on page 397 Blitzer, Intermediate Algebra, 5e – Slide #16 Section 6.1

  17. Multiplying Rational Expressions p 398 Blitzer, Intermediate Algebra, 5e – Slide #17 Section 6.1

  18. Multiplying Rational Expressions EXAMPLE Multiply: SOLUTION This is the original expression. Factor the numerators and denominators completely. Divide numerators and denominators by common factors. Blitzer, Intermediate Algebra, 5e – Slide #18 Section 6.1

  19. Multiplying Rational Expressions CONTINUED Multiply the remaining factors in the numerators and in the denominators. Note that when simplifying rational expressions or multiplying rational expressions, we just used factoring. With one additional step that is provided in the following Definition for Division, division of rational expressions promises to be just as straightforward. Blitzer, Intermediate Algebra, 5e – Slide #19 Section 6.1

  20. Multiplying Rational Expressions EXAMPLE Multiply: SOLUTION This is the original expression. Factor the numerators and denominators completely. Divide numerators and denominators by common factors. Because 3 – y and y -3 are opposites, their quotient is -1. Blitzer, Intermediate Algebra, 5e – Slide #20 Section 6.1

  21. Multiplying Rational Expressions CONTINUED Now you may multiply the remaining factors in the numerators and in the denominators. or Blitzer, Intermediate Algebra, 5e – Slide #21 Section 6.1

  22. Multiplying Rational Expressions Check Point 5 Multiply: pages 398-399 Blitzer, Intermediate Algebra, 5e – Slide #22 Section 6.1

  23. Multiplying Rational Expressions Check Point 6 Multiply: pages 398-399 Blitzer, Intermediate Algebra, 5e – Slide #23 Section 6.1

  24. Dividing Rational Expressions Replace with its reciprocal by interchanging its numerator and denominator. Change division to multiplication. Blitzer, Intermediate Algebra, 5e – Slide #24 Section 6.1

  25. Dividing Rational Expressions EXAMPLE Divide: SOLUTION This is the original expression. Invert the divisor and multiply. Factor. Blitzer, Intermediate Algebra, 5e – Slide #25 Section 6.1

  26. Dividing Rational Expressions CONTINUED Divide numerators and denominators by common factors. Multiply the remaining factors in the numerators and in the denominators. Blitzer, Intermediate Algebra, 5e – Slide #26 Section 6.1

  27. Multiplying Rational Expressions Check Point 7a Divide: Blitzer, Intermediate Algebra, 5e – Slide #27 Section 6.1

  28. Multiplying Rational Expressions Check Point 7b Divide: Blitzer, Intermediate Algebra, 5e – Slide #28 Section 6.1

  29. DONE

More Related