1 / 11

Understanding NaCl Dissolution and Precipitation Reactions in Chemistry 203

This resource provides an overview of solubility rules and precipitation reactions relevant for Chemistry 203. It emphasizes the importance of knowing how to apply solubility rules when writing equations from ionic reactants. Practice questions include determining the concentration of NaCl solutions and predicting products from reactions between lead(II) nitrate and potassium iodide. It also covers calculating concentrations of remaining ions after precipitation. Ideal for exam preparation, including practical calculation exercises.

paula-carr
Télécharger la présentation

Understanding NaCl Dissolution and Precipitation Reactions in Chemistry 203

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript

  1. To Know… • Lon-Capa • Chemistry 203 • REACT • Monday – Chapter 5

  2. NaCl Dissolves

  3. p129

  4. Solubility Rules

  5. p130

  6. Precipitation Reactions • Know how to use the solubility rules (you will be given them on the exam). • Know how to write equations from reactants (ionic reactants). • Understand what solutions “look” like at a very magnified level.

  7. Clicker Question When lead(II) nitrate and potassium iodide are mixed, which are the possible products? 1. PbI 2. PbI2 3. K(NO3)2 4. KNO3 a) 1 & 3 b) 1 & 4 c) 2 & 4 d) 2 & 3

  8. Solubility Rules

  9. Clicker Question Which solution is the most concentrated?

  10. Problems to Know… • You dissolve 10.0 g of NaCl in 150.0 mL of solution. Determine the concentration in molarity. • [1.14M NaCl] • Describe how to make 250.0 mL of 0.100M NaOH from a stock solution of 8.00M NaOH. • [Take 3.125 mL of 8.00M NaOH and add enough water to make 250.0 mL of solution.]

  11. Chapter 4: #39 How many grams of silver chloride can be prepared by the reaction of 100.0 mL of 0.20M silver nitrate with 100.0 mL of 0.15M calcium chloride? Calculate the concentrations of each ion remaining in solution after precipitation is complete.

More Related