1 / 1

餘角的三角函數

製作人 : 李躍進. 餘角的三角函數. 餘角的三角函數值. 設三角形 ∆ ABC 中 ∠ C=90 0 , 則 ∠ A 與 ∠ B 互為餘角 ,. 即 ∠ B=90 0 - ∠A. 餘角的三角函數值. B. ∠ B=90 0 - ∠A. sin ↔ cos tan ↔ cot sec ↔ csc. coFunB ↔FunA coFunA ↔FunB. c. a. 90 0. A. b. C. 製作人 : 李躍進. sinB=sin(90 0 -A)=cosA=b/c.

penney
Télécharger la présentation

餘角的三角函數

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript


  1. 製作人: 李躍進 餘角的三角函數 餘角的三角函數值 設三角形∆ABC中∠C=900, 則∠A與∠B互為餘角, 即∠B=900 -∠A 餘角的三角函數值 B ∠B=900 -∠A sin ↔ cos tan ↔ cot sec ↔ csc coFunB ↔FunA coFunA ↔FunB c a 900 A b C 製作人 : 李躍進 sinB=sin(900-A)=cosA=b/c cosB=cos(900-A)=sinA=a/c tanB=tan(900-A)=cotA=b/a cotB=cot(900-A)=tanA=a/b 製作日期 : 2001/8/2 secB=sec(900-A)=cscA=c/a cscB=csc(900-A)=secA=c/b 製作日期:2001/8/1

More Related