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ACC QAS W/S #2 Key

ACC QAS W/S #2 Key

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ACC QAS W/S #2 Key

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  1. ACCUPLACER® Module #2 - QAS Worksheet #2 - Key 1

  2. Module #2 Worksheet #2 1. B: 2 NAME: ____KEY__________________ amust be subtracted from both sides, with a result of 1 reciprocal of both sides needs to be taken, but the right-hand side needs to be written as a single fraction in order to do that. Since the two fractions on the right have denominators that are not equal, a common denominator of ab is needed. This leaves: 1 x ab ab ab 2 b 2. a   The x a b  2 2 2( ). a b    Taking the r5eciprocals, which can be done ab a b   since b - a is not zero, with the result of . x 2( ) 2. B: Plugging into the quadratic formula, yields, for solutions: 1 1 4 1( 3) 1 11. 2 2 2     x 1 2 11. 2    x   Therefore, Now if this is squared hen x 11 2 11 4  2 the ± cancels and we are left with ( ) . 3. A: Parallel lines have the same slope. The slope of C can be seen to be 1/3 by dividing both sides by 3. The others are in standard form Ax + By = C, for which A B D is 1. 4. B: The slope will be given by 1 0 2 0 2   the slope is given by . The slope of A is 3, the slope of B is 4, and the slope of  1.  The y-intercept will be 0, since it passes 1 2  through the origin. Using slop-intercept form, the equation for this line is . y x 5. C: Let r be the number of red cans and b be the number of blue cans. One equation is r + b = 10. The total price is $16, and the prices for each can means 1r + 2b = 16. Multiplying the first equation on both sides by -1 results in - r - b = -10. Add this equation to the second equation, leaving b = 6. So, she bought 6 blue cans. From the first equation, this means r = 4; thus she bought 4 red cans. 2

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