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Understanding True Bearings in Navigation and Trigonometry Applications

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This guide explores the concept of true bearings, which are crucial in navigation for accurately communicating directions. True bearings are measured clockwise from due north and expressed in three digits (e.g., S.E. 135°). The document covers examples demonstrating how to calculate true bearings for various points and emphasizes the relationship between opposite directions differing by 180°. Using triangles and trigonometric functions (SOH CAH TOA), we illustrate how to determine distances based on bearings, providing practical examples for better understanding.

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Understanding True Bearings in Navigation and Trigonometry Applications

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  1. Ch 4: Trigonometry 4D: Bearings

  2. True Bearings • Important in navigation as used to communicate direction • True bearings (oT) are measured clockwise from due north. • Usually written using 3 digits (i.e. S E 135O) • Opposite directions differ by 180o

  3. Example (pg. 9) N Find the True Bearing for point A, B, C & D D A 90o – 35o = 055o A = B = C = D = 70o 35o 90o+45o = 135o E 30o W 45o O 270o-30o = 240o C 360o-20o = 340o B S

  4. Example (pg. 10) N N How far east is the person from their original position? W W E E STEP 1: Draw Triangle S S 10km 10km 30o Xcm 60o 15km STEP 2: Use SOH CAH TOA to find x Xcm x = 10cos60 x = 5km

  5. Example (pg.10) N N How far north is the person from their original position? W W E E STEP 1: Draw Triangle 10km S S Xcm 30o 10km Xcm 30o STEP 2: Use SOH CAH TOA to find x 15km x = 10cos30 x = 8.66km Total distance = 15km +8.66km = 23.66km

  6. Example (pg.11) N N Find how far east is the ship from its starting point, correct to two decimal places. W W E E Xcm STEP 1: Draw Triangle 30o S S 5km 11km 90o Xcm 30o STEP 2: Use SOH CAH TOA to find x 11km x = 11cos30 x = 9.526km

  7. Example (pg.11) N N Find how far east is the ship from its starting point, correct to two decimal places. W W E E STEP 1: Draw Triangle S S 5km 11km 60o 90o Xcm 30o 11km STEP 2: Use SOH CAH TOA to find x Xcm x = 11cos60 x = 5.5km Total distance = 5km +5.5km = 10.5km

  8. Question Ex 4D 4.4 Level 1: 2, 4-6 Level 2: 2 ace, 5, 6, 8, 9 Level 3: 2 c e, 6, 9 , 11, 13

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