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10 cm

e. 10 cm. -e. 1cm. e. Calculate E y here. Cathode Ray Tube Conducting Paper. C. +. B. +10 Volts. +. A. +. 0 Volts. E y. E x. +. -. V OUT. -. +. V IN. V OUT. V IN. V=8 volts. = 1cm. V=6 volts. V=4 volts. E=?. V=-2 volts. V=0 volts. V=2 volts. a. b. c. 6 V. d.

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10 cm

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  1. e 10 cm -e 1cm e

  2. Calculate Ey here.

  3. Cathode Ray Tube Conducting Paper C + B +10 Volts + A + 0 Volts

  4. Ey Ex + -

  5. VOUT - + VIN

  6. VOUT VIN

  7. V=8 volts = 1cm V=6 volts V=4 volts E=? V=-2 volts V=0 volts V=2 volts

  8. a b c 6 V d e f 5 V g h i 4 V

  9. A. B. 3 V 3 V C. 3 V

  10. 3 C -5 C 4 C 3 cm

  11. 3 C -5 C 4 C q 3 cm

  12. 3 C -5 C 4 C q 3 cm

  13. 3 V 6 V 1,000 

  14. Baseball Diamond Heuristic of Electrostatics Equations

  15. RELATING IMPORTANT CONCEPTS (vector) (The force between 2 charges at a distance r from each other.) (vector) (scalar) (The potential energy stored in having 2 charges at a distance r from each other.) (Usually find with Gauss’s Law.) (The change of electric potential a particle experiences moving from one position to another can be used to find the change in its kinetic energy via the “work-energy theorem”: K = W.) (scalar) (Remember: V, the electric potential, has units of energy per unit charge.) Note: F, U, E, and V are all functions of position.

  16. B. 3 V 3 V C. 3 V

  17. 3 V 3  2  1 

  18. 3 V 3  2  1 

  19. V R1 R2

  20. V R1 VDMM RDMM V VDMM RDMM

  21. 3 V 3  2  1  1 

  22. 100  200 100  10 

  23. V 100  200 100  10 

  24. V R1 R2

  25. 3 V 3  2  1  1  2 

  26. 3 V 3  2  1  1  1  2 

  27. Reffective=? R4=4  I4=? V4=? 9 V R1= 1  R2= 2  R3= 3  IBattery=? I1=? V1=? I2=? V2=? I3=? V3=?

  28. t V S C O P E

  29. Vmotor on on on on off off off off off Vmotor,on t t1 t2 Vresistor=|Vsource|-Vmotor on on on on off off off off off Vresistor,on t T

  30. Voltage (0.5 volts per div) O S C O P E Time (1 second per div)

  31. Y-axis: Voltage (0.5 volts per division) 1.5 O S C O P E X-axis: Time (1 second per division) 0

  32. red1 R + red2 - C bottom ground

  33. R VR (t) = -Vsource (t) = -VMAXsin(t) Vsource (t) = VMAXsin(t) where VMAX = 5 Volts /(2) = 1,000 Hz

  34. Vsource (t) = VMAXsin(t) where VMAX = 5 Volts /(2) = 1,000 Hz

  35. red1 x-y mode Vamp=3 V red2 CH1 CH2 330  bottom ground

  36. red 1 red 1 100  100  + + red 2 (channel inverted) black (bottom ground) black (middle ground) red 2 - - 200  200 

  37. R Vsource (t) C

  38. S C O P E

  39. Y-axis: Voltage (5 volts per division) X-axis: Time (3 millisecond per division)

  40. I L I B I I B BFar is ~ zero BClose is strong Magnet Magnet Magnet

  41. Beginning Position 180o Rotated Position I I I I I I current direction reversed (so is force on wire)

  42. I I

  43. DC Power Supply + - I these wires fixed I brushes allow good contact as loop rotates I current direction always the same (so is force on wire)

  44. A. B. C. S N S N S N I I I S N N N S S

  45. 1.5  A 4 V 0.5  4  1.5  4 V 20 V B 2.5 

  46. A 1  2  2  3  BATTERY 12 V 1  1  2  B

  47. S 2 F 6 V 6  2  1 

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