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Solving Algebraic Equations Using Opposite Operations. First Degree Equations (One Step Equations). Solving Equations. An equation is like a balance scale As long as you do the “same thing” to both sides of the “scale” or equation, you do not change the value of the equation

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## Solving Algebraic Equations Using Opposite Operations

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**Solving Algebraic Equations Using Opposite Operations**First Degree Equations (One Step Equations)**Solving Equations**An equation is like a balance scale As long as you do the “same thing” to both sides of the “scale” or equation, you do not change the value of the equation Therefore we can use opposite operations, to balance out an equation, to solve of unknown variables**Solving Equations by Subtraction**Given the following equation, use opposite operations to solve for the unknown variable n + 6 = 14 n + 6 – 6 = 14 -6 n = 8 p + 3.4 = 22 p + 3.4 – 3.4 = 22 – 3.4 p = 18.6 CHECK: p + 3.4 = 22 18.6 + 3.4 = 22 22 = 22**Solving Equations by Addition**Given the following equation, use opposite operations to solve for the unknown variable r – 5 = 12 r – 5 + 5 = 12 + 5 r = 17 p – 9 = 0.9 p – 9 + 9 = 0.9 + 9 p = 9.9 CHECK: p – 9 = 0.9 9.9 – 9 = 0.9 0.9= 0.9**Solving Equations by Dividing**Given the following equation, use opposite operations to solve for the unknown variable 5n = 25 5n = 25 5 5 n = 5 100 x n = 2000 100 x n ÷ 100 = 2000 ÷ 100 n = 20 CHECK: 100 x n = 2000 100 x 20 = 2000 2000 = 2000**Solving Equations by Multilpying**Given the following equation, use opposite operations to solve for the unknown variable n / 7 = 7 n / 7 x 7 = 7 x 7 n = 49 n ÷ 100 = 5 n ÷ 100 x 100 = 5 x 100 n = 500 CHECK: n ÷ 100 = 5 500 ÷ 100 = 5 5 = 5**Homework**http://studyjams.scholastic.com/studyjams/jams/math/algebra/add-sub-equations.htm http://studyjams.scholastic.com/studyjams/jams/math/algebra/mult-div-equations.htm

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