1 / 6

Electrochemistry

Electrochemistry. Electrochemistry. To obtain a useful current, we separate the oxidation and reduction half-reactions so that electron transfer occurs thru an external wire. This is accomplished in a GALVANIC or VOLTAIC cell. A group of such cells is called a battery.

Télécharger la présentation

Electrochemistry

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript


  1. Electrochemistry

  2. Electrochemistry • To obtain a useful current, we separate the oxidation and reduction half-reactions so that electron transfer occurs thru an external wire. This is accomplished in a GALVANIC or VOLTAIC cell. A group of such cells is called a battery. http://www.mhhe.com/physsci/chemistry/essentialchemistry/flash/galvan5.swf

  3. Galvanic Cells Anode= oxidation Cathode= reduction - + spontaneous redox reaction 19.2

  4. E0 = Ecathode - Eanode cell Standard emf (E0 ) cell 0 0 GalvanicCells • The difference in electrical potential between the anode and cathode is called: • cell voltage • electromotive force (emf) • cell potential 19.2

  5. Standard Electrode Potentials Standard reduction potential (E0) is the voltage associated with a reduction reaction at an electrode when all solutes are 1 M and all gases are at 1 atm. • E0 is for the reaction as written • The more positive E0 the greater the tendency for the substance to be reduced • In a cell, the substance with the greater E0 value is at the cathode (where reduction takes place) 19.3

  6. Cd2+(aq) + 2e- Cd (s)E0 = -0.40 V Cr3+(aq) + 3e- Cr (s)E0 = -0.74 V E0 = -0.40 - (-0.74) E0 = 0.34 V E0 = Ecathode - Eanode cell cell cell 0 0 What is the standard emf of an electrochemical cell made of a Cd electrode in a 1.0 M Cd(NO3)2 solution and a Cr electrode in a 1.0 M Cr(NO3)3 solution? Cd2+ will be reduced (at the cathode) Cr(s) will be oxidized (at the anode) 19.3

More Related