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Algebra 2 Honors

In this summary, I reflect on my learning experiences in the Algebra 2 Honors course as of August 2013. So far, I've studied absolute value equations, inequalities, and polynomial expressions. For instance, I learned to solve the equation |3 - 6x| = 0.15, resulting in two solutions: x = 2 and x = -3. I also explored practical applications, like using algebra to solve budget problems in real-life scenarios, such as figuring out costs for flowers at a wedding. This emphasizes the relevance of algebra in everyday decision-making.

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Algebra 2 Honors

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  1. Algebra 2 Honors Bell work

  2. August 26, 2013 • Write a half page summary answering the following questions? • 1. What have you learned so far in this course? (use specific examples) • 2. How could you use this in the real world?

  3. August 27, 2013 • What is the complete solution to the equation I3−6xI= 15? • A x =2; x =3 • B x =−2; x =3 • C x =2; x =−3 • D x =−2; x =−3

  4. AUGUST 28, 2013 • For a wedding, Shereda bought several dozen roses and several dozen carnations. The roses cost $15 per dozen, and the carnations cost $8 per dozen. Shereda bought a total of 17 dozen flowers and paid a total of $192. How many roses did she buy? • A 6 dozen • B 7 dozen • C 8 dozen • D 9 dozen

  5. August 29, 2013 • What is the correct inequality? • A. y< 5/4x + 3 • B. y> 5/4x – 3 • C. Y<-5/4x + 3 • D. y> -5/4x - 3

  6. August 30, 2013 • Which polynomial represents • (3x2 + x −4)(2x −5)? • A 6x3 −13 x2 −13 x−20 • B 6x3 −13 x2 −13 x+20 • C 6x3 +13 x2 +3x−20 • D 6x3 +13 x2 +3x+20

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