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Introduction to Chemistry Concepts and Mole Calculations

Join Dr. Don DeCoste for Chemistry 101 at the University of Illinois. This course explores fundamental concepts, including atomic mass, the mole concept, and chemical reactions. Classes are held Mondays from 2-3 PM and Thursdays from 10-11 AM, with additional discussion sessions and homework assignments via Lon-Capa. Access lecture slides online after each session. Get ready to tackle questions about atomic mass and compare elements like copper and magnesium. Enhance your understanding of how chemistry relates to mass and number of particles.

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Introduction to Chemistry Concepts and Mole Calculations

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  1. Chemistry 101 • Dr. Don DeCoste • 109 Chemistry Annex • decoste@illinois.edu • 244-5959 • 2-3 pm Mondays and 10-11 am Thursdays • By appointment

  2. To Do… • http://chem.illinois.edu • Slides on the website (after each lecture) • Discussion tomorrow. • Lon-Capa (HW2 Type 1 due Monday, February 3 by 7 pm).

  3. Subscripts Represent Numbers

  4. Chemical Reactions Occur By Number of Molecules

  5. Clicker Question The mass of a single atom of hydrogen is: a) 1.674 x 10-24 g b) 6.022 x 1023 g c) 1.000 mole d) 1.008 g e) 2.016 g

  6. Clicker Question The mass of a single atom of hydrogen is: a) 1.674 x 10-24 g b) 6.022 x 1023 g c) 1.000 mole d) 1.008 g e) 2.016 g

  7. Clicker Question You have a 12.01 g sample of carbon and a 1.008 gram sample of hydrogen. The number of carbon atoms is: a) greater than the number of hydrogen atoms. b) less than the number of hydrogen atoms. c) the same as the number of hydrogen atoms. d) I have no idea.

  8. Clicker Question You have a 12.01 g sample of carbon and a 1.008 gram sample of hydrogen. The number of carbon atoms is: a) greater than the number of hydrogen atoms. b) less than the number of hydrogen atoms. c) the same as the number of hydrogen atoms.

  9. The Mole Concept: Why? • We can count by weighing (relative masses). • Reactions occur by number of particles, we must deal with masses, so we must have a way of converting between number and mass. • Atoms/molecules are very small!

  10. Clicker Question You have equal mass samples of copper (Cu) and magnesium (Mg). Which sample contains the greater number of atoms? a) The sample of copper. b) The sample of magnesium. c) The samples contain the same number of atoms. d) I have no idea.

  11. Clicker Question You have equal mass samples of copper (Cu) and magnesium (Mg). Which sample contains the greater number of atoms? a) The sample of copper. b) The sample of magnesium. c) The samples contain the same number of atoms.

  12. Clicker Question You have a 10.0 g sample of copper (Cu). What mass of magnesium (Mg) do you need to have the same number of Mg atoms as Cu atoms? a) More than 10.0 g of Mg. b) Less than 10.0 g of Mg. c) 10.0 g of Mg. d) I have no idea.

  13. Clicker Question You have a 10.0 g sample of copper (Cu). What mass of magnesium (Mg) do you need to have the same number of Mg atoms as Cu atoms? a) More than 10.0 g of Mg. b) Less than 10.0 g of Mg. c) 10.0 g of Mg.

  14. Calculate… You have a 10.0 g sample of copper (Cu). Determine the mass of magnesium (Mg) such that the number of copper atoms and magnesium atoms are equal.

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