1 / 11

Algebra 1

Algebra 1. Coin Word Problems. Stan’s pocket is filled with nickels and dimes. He has 6 more dimes than nickels. All together Stan has $1.20 in coins. How many nickels and dimes does he have? -Let’s start with the sentence “He has 6 more dimes than nickels.”

sandra_john
Télécharger la présentation

Algebra 1

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript


  1. Algebra 1 Coin Word Problems

  2. Stan’s pocket is filled with nickels and dimes. He has 6 more dimes than nickels. All together Stan has $1.20 in coins. How many nickels and dimes does he have? -Let’s start with the sentence “He has 6 more dimes than nickels.” -Ask yourself “Which coin does he have more of?” -The answer is dimes. d = n + 6 Quantity Equation

  3. All together Stan has $1.20 in coins. • Each coin has a different value. • Each nickel is worth 5 cents. Thus 5n is the amount all his nickels are worth. • Each dime is worth 10 cents. Thus 10d is the amount all his dimes are worth. • $1.20 is worth 120 cents… • 5n + 10d = 120 The value equation.

  4. Substitute and solve • 10d + 5n = 120 and d = (n + 6) • 10(n + 6) + 5n = 120 • 10n + 60 + 5n = 120 • 15n + 60 = 120 • 15n = 60 • n = 4

  5. Complete the Problem • He has 4 nickels. • d = n + 6 • d = 4 + 6 • d = 10 • Stan has 4 nickels and 6 dimes.

  6. Check • 10 dimes is worth 10(.10) = $1.00 • 4 nickels is worth 4(.05) = $0.20 Total = $1.20

  7. 4) She gave the sitter 6 more nickels than dimes. • She has more… • Nickels. • n = d + 6 Quantity Equation. • She has 3 times as many quarters as dimes. • She has more… • Quarters. • q =3d Quantity Equation.

  8. All together Mrs. Ryan paid the babysitter $7.50. • Total nickel value in cents… • 5n • Total dime value in cents… • 10d • Total quarter value in cents… • 25q • 5n + 10d + 25q = 750

  9. Substitute and Solve • n = d + 6 q = 3d • 5n + 10d + 25q = 750 • 5(d + 6) + 10d + 25(3d) = 750 • 5d + 30 + 10d + 75d = 750 • 90d + 30 = 750 • 90d = 720 • d = 8 • She paid 8 dimes.

  10. Solve for Nickels and Quarters • d = 8 • n = d + 6 • n = 8 + 6 • n = 14 • q = 3d • q = 3(8) • q =24

  11. Check • 8 dimes is worth 8($0.10) = $0.80 • 14 nickels is worth 14($0.05) = $0.70 • 24 quarters is worth 24($0.25) = $6.00 Total = $7.50

More Related