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Factorization by grouping the terms

Factorization by grouping the terms. Factorization by Grouping the terms…. Eg1. X³ - 2x² + x – 2 [ step 1 : In first two terms x² is common In second term 1 is common - lets take out those 2 term ] X³ - 2x² + x – 2 = x² (x) - x²(2) + 1(x) – 1(2) = x²(x -2) + 1(x - 2)

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Factorization by grouping the terms

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  1. Factorization by grouping the terms

  2. Factorization by Grouping the terms… Eg1.X³ - 2x² + x – 2 [step 1: In first two terms x² is common In second term 1 is common - lets take out those 2 term] X³ - 2x² + x – 2 =x² (x) - x²(2) + 1(x) – 1(2) = x²(x -2) + 1(x - 2) [step 2: let’s group the common term from the both first and second term (i.e) (x – 2), then group the remaining terms in another group] x²(x -2) + 1(x - 2) = (x² + 1) (x – 2)

  3. Factorization by Grouping the terms… Eg2.y³ + 3y + y2 + 3 [step 1: In first two terms y is common In second term 1 is common - lets take out those 2 term] y³ + 3y+ y2 + 3 =y(y2) + y(3)+ 1(y2) + 1(3) = y(y2 + 3) + 1(y2 + 3) [step 2: let’s group the common term from the both first and second term (i.e) (y2 + 3), then group the remaining terms in another group] y(y2 + 3) + 1(y2 + 3) = (y + 1) (y2 + 3)

  4. Factorization by Grouping the terms… Eg3.4x2 + 20x – 3xy – 15y [step 1: In first two terms 4x is common In second term -3y is common - lets take out those 2 term] 4x2 + 20x –3xy – 15y =4x(x) + 4x(5)–3y(x) – 3y(5) = 4x(x + 5) -3y(x + 5) [step 2: let’s group the common term from the both first and second term (i.e) (x + 5), then group the remaining terms in another group] 4x(x + 5) -3y(x + 5) = (4x – 3y) (x + 5)

  5. Try These Factorize the following: m2 + 3m + 5m + 15 4x2 + 6xy – 8xy – 12y2

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