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0022 mol - PowerPoint PPT Presentation

25.0 mL of 0.50 M NaOH were combined with 14.7 mL of 0.35 M

25.0 mL of 0.50 M NaOH were combined with 14.7 mL of 0.35 M H 2 SO 4 . Determine the moles of the excess reactant remaining and its new concentration. 2NaOH + H 2 SO 4 ? 2H 2 O + Na 2 SO 4. 25.0 mL. 14.7 mL. Just pick a product.

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0022 mol - PowerPoint PPT Presentation

25.0 mL of 0.50 M NaOH were combined with 14.7 mL of 0.35 M