2x 2 7 - PowerPoint PPT Presentation
探究新知
探究新知. [ 读教材 · 填要点 ]. 1 ．含绝对值的不等式 | x | ＜ a 与 | x | ＞ a 的解法. { x | － a ＜ x ＜ a }. ∅. ∅. R. { x ∈ R| x ≠ 0}. { x | x ＞ a 或 x ＜－ a }. 2 ． | ax ＋ b |≤ c ( c ＞ 0) 和 | ax ＋ b |≥ c ( c ＞ 0) 型不等式的解法 (1)| ax ＋ b |≤ c ⇔ ； (2)| ax ＋ b |≥ c ⇔. － c ≤ ax ＋ b ≤ c. ax ＋ b ≥ c 或 ax ＋ b ≤ － c.
By ilyssa
Don’t forget: You can copy-paste this slide into other presentations, and move or resize the poll.
Don’t forget: You can copy-paste this slide into other presentations, and move or resize the poll. Poll: Which one exhibits the quotient rule. Don’t forget: You can copy-paste this slide into other presentations, and move or resize the poll. Poll: Which one represents the Product Rule.
By elijah-logan
M3U3D1 Warm-UP Distribute each problem:
M3U3D1 Warm-UP Distribute each problem:. COLLECT WARMUPS. Evaluating and Operating with Polynomials OBJ: To review adding, subtracting, multiplying, and factoring polynomials. How do I evaluate polynomial functions? You have 3 minutes to complete the top of handout page 1. Discuss.
By britanni-howell
X-box Factoring Quadratics February 5, 2016
X-box Factoring Quadratics February 5, 2016. Factor the x-box way. y = ax 2 + bx + c. x. q. Product a c. First and Last Coefficients. 1st Term. Factor q. x. q. p. Middle. Last term. Factor p. p. b= p + q Sum. Factor the x-box way. Example: Factor 3x 2 -13x -10.
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Transfos (2x 2 MVA)
POINT 8 – New LHCb Buildings in replacement of building 156 ( Meyrin ). New Storage Hall ( 112 m2). PROJECT. New Assembly Hall (485 m2). Technical Gallery. C. B. LS1 Area. LHCb giant poster. D. A. Transfos (2x 2 MVA). Servers (containers). New LHCb Control Room (CR) +
2X
T 2. 2σds. θ. T 1. λgds. 2X. L. Figure 1 The four forces acting on the chain element ds are shown . The chain assumes a concave configuration when surface tension ( 2 σ ) is larger than the normal component of the gravitational force per unit length ( λg cosθ ). T 2. T 1. 2X. L 0.
sO… 2x 3 (x 3 + 3x 2 - 2x + 5) =
Do Now: 1. 2x 3 x 3 = ________ 2. 2x 3 3x 2 = ________ 3. 2x 3 (-2x) = ________ 4. 2x 3 5 = ________. sO… 2x 3 (x 3 + 3x 2 - 2x + 5) =.
EJEMPLO : Min 3x 1 +2x 2 +x 3 +2x 4 +2x 5 / x 1 -x 2 +2x 3 -x 4 +x 5 +2x 6 = 1
EJEMPLO : Min 3x 1 +2x 2 +x 3 +2x 4 +2x 5 / x 1 -x 2 +2x 3 -x 4 +x 5 +2x 6 = 1 - x 1 +2x 2 +x 3 -2x 4 -x 5 +x 6 = 3 2 x 1 +x 2 -x 3 +x 4 -2x 5 +x 6 = 2 x i 0 i=1..6 Solución dual factible inicial: T =(0, 0, 0) ya que:
E 1 : x 1 – x 2 + x 3 = 0 E 2 : -2x 1 + 2x 2 – 2x 3 + 22 = 0
Aufgabe 1: Zeige, dass die Ebenen E 1 und E 2 zueinander parallel sind; berechne ihren Abstand:. E 1 : x 1 – x 2 + x 3 = 0 E 2 : -2x 1 + 2x 2 – 2x 3 + 22 = 0. Q ( 0 / 0 / 0 ) E 1. Q in E HNF2 =. Der Abstand der beiden parallelen Ebenen beträgt (~6,35 LE).
2x² – 2x – 4 = 0
2x² – 2x – 4 = 0. Calcul du discriminant :. a = b = c =. 2 – 2 – 4. D = 36. D > 0, donc l’équation admet deux solutions. x 2 = 2. x 1 = – 1. x² + 4x + 3 = 0. Calcul du discriminant :. a = b = c =. 1 4 3. D = 4.
(2) 3x<2x+1
0. 1. (2) 3x<2x+1. 为了使不等式 3x<2x+1 中不等号的一边变为 x ，根据 ，不等式两边 都减去 ，不等号的方向 。. 2x. 不等式性质 1. 不变. 3x-2x﹤2x+1-2x x﹤1. 得. 注意 ： 解不等式时也可以“移项”，即把不等式的一边的某项变号后移到另一边，而不改变不等号的方向．. ２. (3) － x﹥24. 3. 2. 为了使不等式 － x﹥50 中不等号的一边变为 x ，根据不等式的性质 ２ ，不等式的两边都乘 不等号的方向不变，得. 3. 3.
Doubled (2x)
Doubled (2x). M. (a) Quadrupled (4x) (b) Quadrupled (4x). O. 385 kg●m /s. M. 90 m/s. E. 0 m/s. N. 21 m/s. T. 4.3 m/s. U. (a) 5500 kg●m /s (b) 92 N. M. Stays the same. W. (a) Quadrupled (4x) (b) Stays the same. R. 385 p. O. 22.5 m/s. N. 1 m/s. G. 933 m/s. E. 12.9 m/s.
F 2x
USAHA/KERJA (W). Perhatikan betul-betul gambar berikut!!!. F 2 > F 1. F 1. F 2. β. α. F 2x. F 1x. s. (F 2x – F 1x ) . S. W =. F 1 cos α. F 1x =. F 2 cos β. F 2x =. RADIASI KALOR. Benda Hitam. Perhatikan betul-betul gambar berikut!!!. Pendekatan !!!.
2X Religion
2X Religion. You will become more familiar with life and achievements of ‘St. Teresa of Avila’. You will contribute to placing St. Teresa’s life in chronological order. You will be able to recognise St. Teresa’s main beliefs on prayer. Born: 28 th March 1515 Avila, Spain.