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C Language Part 4

C Language Part 4. Pointers (revisited). int i = 4, j = 6, *p = &i, *q = &j, *r; if (p == &i) ...; if (p == (& i)) ...; ... = **&p; ... = *(*(& p)); ... = 9 * *p / *q + 8; ... = (((9*(*p)))/(*q)) + 8; *(r = &i) *= *p; (* (r = (& j))) *= (* p);. Pointers (contd.). int *p; float *q;

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C Language Part 4