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Chapter 3: Combining Factors

Chapter 3: Combining Factors

Chapter 3: Combining Factors. Developed by Dr. Don Smith, P.E., Texas A&M University & Dr. Michael Bennett, P.Eng., PMP, UOIT, Oshawa, Ontario. Learning Objectives. Shifted Series Shifted Series and Single Amounts Shifted Gradients Decreasing Gradients Spreadsheets. Section 3.1.

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854 views • 45 slides
CHAPTER 3

CHAPTER 3

CHAPTER 3. COMBINING FACTORS. Learning Objectives. Shifted Series Shifted Series and Single Amounts Shifted Gradients Decreasing Gradients Spreadsheets. Section 3.1. Calculations For Uniform Series That Are Shifted. 1. Uniform Series that are SHIFTED.

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578 views • 43 slides
CHAPTER III

CHAPTER III

M c. Graw. Hill. ENGINEERING ECONOMY Fifth Edition. Blank and Tarquin. CHAPTER III. COMBINING FACTORS Adopted and modified by Dr. W-.W. Li of UTEP, Fall, 2003. 3.1 Uniform Series that are SHIFTED. A shifted series is one whose present worth point in time is NOT t = 0.

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367 views • 35 slides
ENGINEERING ECONOMICS

ENGINEERING ECONOMICS

ENGINEERING ECONOMICS. Lecture # 3 Cash Flow and Cash Flow Diagram Rule of 72 Arithmetic Gradient Factor Geometric Gradient Factor Total present worth Examples and Numerical. Cash Flow.

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1.78k views • 34 slides
Single-Payment Factors (P/F, F/P)

Single-Payment Factors (P/F, F/P)

Single-Payment Factors (P/F, F/P). F = ?. Example: Invest $1000 for 3 years at 5% interest. i = .05. $1000. F 1 = 1000 + (1000)(.05) = 1000 (1+ .05 ) F 2 = F 1 + F 1 i = F 1 (1+ i ) = 1000 (1+ .05 )(1+ .05 ) = 1000 (1+ .05 ) 2 F 3 = 1000 (1+ .05 ) 3. $?.

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293 views • 28 slides
Single-Payment Factors (P/F, F/P)

Single-Payment Factors (P/F, F/P)

Single-Payment Factors (P/F, F/P). F = ?. Example: Invest $1000 for 3 years at 5% interest. i = .05. $1000. F 1 = 1000 + (1000)(.05) = 1000 (1+ .05 ) F 2 = F 1 + F 1 i = F 1 (1+ i ) = 1000 (1+ .05 )(1+ .05 ) = 1000 (1+ .05 ) 2 F 3 = 1000 (1+ .05 ) 3. $?.

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388 views • 28 slides
Single-Payment Factors (P/F, F/P)

Single-Payment Factors (P/F, F/P)

Single-Payment Factors (P/F, F/P). F = ?. Example: Invest $1000 for 3 years at 5% interest. i = .05. $1000. F 1 = 1000 + (1000)(.05) = 1000 (1+ .05 ) F 2 = F 1 + F 1 i = F 1 (1+ i ) = 1000 (1+ .05 )(1+ .05 ) = 1000 (1+ .05 ) 2 F 3 = 1000 (1+ .05 ) 3. $?.

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497 views • 28 slides
Engineering Economics ENGR 3300

Engineering Economics ENGR 3300

Engineering Economics ENGR 3300. Department of Mechanical Engineering Inter American University of Puerto Rico Bayamon Campus Dr. Omar E. Meza Castillo omeza@bayamon.inter.edu http://www.facultad/ b ayamon.inter.edu/ omeza. Time Value of Money.

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427 views • 28 slides
Lecture # 6 TUTORIAL on numerical questions

Lecture # 6 TUTORIAL on numerical questions

Lecture # 6 TUTORIAL on numerical questions. Remember you are welcome to contact me for queries any time Email : ejazjazz@yahoo.com Cell : 0300 - 5906405. Equivalence. Interest rate = 10%. Present value of Plan 1 P = $1,000(3.791) = $3,791 Present value of Plan 2 P = $5,000

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449 views • 19 slides

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