'Pbi 2' diaporamas de présentation

Drill:

Drill:. Determine the KQ/HQ ratio to make a buffer solution with a pH of 4.70 K a for HQ = 3.0 x 10 -5. Drill: Calculate [H 2 Q], [HQ - ], [Q -2 ], [H + ], & pH of 0.20 M KHQ. Ka 1 = 2.0 x 10 -4 Ka 2 = 8.0 x 10 -9. Review Drill & Test. CHM II HW. Review PP-25

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Drill:

Drill:. Determine the KQ/HQ ratio to make a buffer solution with a pH of 4.70 K a for HQ = 3.0 x 10 -5. Drill: Calculate [H 2 Q], [HQ - ], [Q -2 ], [H + ], & pH of 0.20 M KHQ. Ka 1 = 2.0 x 10 -4 Ka 2 = 8.0 x 10 -9. Solubility. Solubility.

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Principles of Reactivity: Other Aspects of Aqueous Equilibria

Principles of Reactivity: Other Aspects of Aqueous Equilibria. Chapter 18. 18.1 Common Ion Effect. The common ion effect is the limiting of the ionization of an acid (or base) by the presence of a significant concentration of its conjugate base (or acid).

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Chapter 27

Chapter 27. Gravimetric and Combustion Analysis. Representative Gravimetric Analyses. Precipitation. AgNO 3 + NaCl -----> AgCl + NaNO 3. Precipitation. AgNO 3 + NaCl -----> ? AgNO 3 + NaCl -----> AgCl + NaNO 3 total ionic equation

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Solubility

Solubility. Write the equilibrium expression for AgCl Ag + + Cl -. Solubility. The amount of one substance that will dissolve in another. Precipitation. When dissolved particles join together forming a new phase and exit the solution. Precipitate (ppt).

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? 3 ? ??????

?? ? ??. ?? ? ??. ? 3 ? ??????. ? 1 ??. ? 1 ????? Ca(HCO 3 ) 2 ? Mg(HCO 3 ) 2 ???? CaCO 3 ? Mg(OH) 2 , ????????????? ? 2 ???????????? FeS ?? , ??? Cu 2+ ? Hg 2+ ? Pb 2+ ?????????????????. CaCO 3 ? FeS ? Mg(OH) 2 ?????????????????????????????????????. ????????????.

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Solubility Product

Solubility Product. Solubility Product Constant. A special case of equilibrium involving dissolving. Solid ? Positive Ion + Negative Ion. Mg(NO 3 ) 2 ? Mg 2+ + 2NO 3 -. Keq = [ Mg 2+ ] [NO 3 - ] 2.

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Chemistry

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PRECIPITATION REACTIONS Solubility of Salts Section 18.4

PRECIPITATION REACTIONS Solubility of Salts Section 18.4. Metal Chloride Salts. These products are said to be INSOLUBLE and form when mixing moderately concentrated solutions of the metal ion with chloride ions. Analysis of Silver Group.

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PbI 2 as a direct semiconductor for use in radiation imaging detectors

PbI 2 as a direct semiconductor for use in radiation imaging detectors. Glenn C. Tyrrell and Jonathan P. Creasey. Applied Scintillation Technologies Ltd. Fluorescent & Scintillation Products for Industry , Science & Medicine. Overview. Motivation Why PbI 2 ? Material Processing

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Chinese Real Time VLBI Correlator

Chinese Real Time VLBI Correlator. Xiang Ying, Xu Zhijun, Zhu Renjie, Zhang Xiuzhong, Shu Fengchun, Zheng Weimin Shanghai Astronomical Observatory China 5th International e-VLBI Workshop 17-20 September 2006. OUTLINE. Main Characteristics Architecture of the Correlator Clock Module

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Lead(II) Iodide-Water System

Lead(II) Iodide-Water System. Edward A. Mottel Department of Chemistry Rose-Hulman Institute of Technology. Resources Available. Exp. K: Aqueous Chemical Reactions : Lead(II) Iodide-Water System. Observations. Solubility Facts. Pb(NO 3 ) 2 (aq) + KI (aq). PbI 2 (s) + H 2 O (l).

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Precipitate Formation: Formation of Lead (II) Iodide

Precipitate Formation: Formation of Lead (II) Iodide. When mixed, two clear solutions produce a dense yellow precipitate. Purpose. To observe the formation of a precipitate from ionic compounds in an aqueous state. Demonstration. The formation of PbI 2(s) from Pb(NO 3 ) 2 and 2KI solutions.

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Balancing Equations

Balancing Equations. 2. Mg. +. O 2. 2. MgO. 2 Mg 2 O. 2 Mg 2 O. 3. Zn. +. 2. FeCl 3. 2. Fe. +. 3. ZnCl 2. 3 Zn 2 Fe 6 Cl. 3 Zn 2 Fe 6 Cl. 2. AlBr 3. +. 3. Cl 2. 2. AlCl 3. +. 3. Br 2. 2 Al 6 Br 6 Cl. 2 Al 6 Br 6 Cl. PbI 2. +. 2. HNO 3. Pb (NO 3 ) 2. +.

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Which of the compounds would form precipitates?

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Warmup (10 minutes)

Warmup (10 minutes). Complete the prelaboratory of the Precipitation Lab by yourself. Use pencil.

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To be able to write a balanced equation for a chemical reaction

Objectives. To be able to write a balanced equation for a chemical reaction. Pb(NO 3 ) 2 (aq) + 2NaI (aq) PbI 2 (s) + 2NaNO 3 (aq). A chemical reaction is balanced by using a systematic approach:. Write the formulas of the reactants and products to give the unbalanced chemical equation.

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C 3 H 8 + 5 O 2 ? 3 CO 2 + 4 H 2 O

C 3 H 8 + 5 O 2 ? 3 CO 2 + 4 H 2 O. 220 g of C 3 H 8 react in the above reaction. What mass of H 2 O is produced?. Pb (NO 3 ) 2 + 2 NaI ? PbI 2 + 2 NaNO 3. 50 mL of a 0.5 mol /L solution of NaI reacts to produce how many grams of PbI 2 ?. C =. n V.

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