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Unit 6 Introduction to Chemistry. Chapter 20 Mixtures and Solutions. 20A – Heterogeneous Mixtures. Objectives: Differentiate between homogeneous and heterogeneous mixtures Identify the continuous phase and the dispersed phase in a mixture

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Solutes and Solubility. Classification of Matter. Classify according to 4 states of matter Classify by the units they are made of. Elements. Matter is made up of atoms if all atoms in a sample have same identity, that matter is an element. Examples. Al Cu Ag . Compounds.

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Metallic Bonding. Introduction to the Lab. Bonds Between Metals. They are NOT the same as ionic bonds But both involve lattice structures. +. +. +. +. +. +. +. +. +. +. +. +. Properties of Metallic Bonds. Involve delocalized electrons – a spreading around of free electrons.

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Chapter 25. Money. Economic Principles. Barter exchange The characteristics of money Gold-backed and fiat money Liquidity. Economic Principles. The equation of exchange The quantity theory of money The classical view of money The Keynesian view of money Monetarism. Introduction.

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9. 9. 3. 3. =. =. 4 x + 1. 4 x + 1. x + 1. x + 1. ANSWER. The solution is –2 . Check this in the original equation. EXAMPLE 1. Solve a rational equation by cross multiplying. Solve:. Write original equation. 3(4 x + 5) = 9( x + 1). Cross multiply. 12 x + 15 = 9 x + 9.

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Write the unit equation and the two corresponding unit factors for each of the following: a) pounds and ounces b) quarts and gallons. Write the unit equation and the two corresponding unit factors for each of the following A) hours and days B) hours and minutes.

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5.6 Solve Rational Equations. p. 345 What is the easiest way to solve a rational equation? What is an extraneous solution? How do you know when to cross multiply or multiply out the denominator?. Cross Multiplying.

1. =. 6. 4. 10. ANSWER. x. 15. 2. 5(3 x – 2) = 4(4 x – 1). ANSWER. –6. Solve the equation. x ( x – 4) = 3( x – 4) + x. 3. ANSWER. 2,6. 4. 2 x 2 + 5 x – 12 = 0. ANSWER. – 4,. 3. 2. Solve the equation. 5.