'Theorem 10' diaporamas de présentation

Bell work 1

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10.4 Other Angle Relationships in Circles

10.4 Other Angle Relationships in Circles. Learning Target. I can use theorems about tangents, chords and secants to solve unknown measure of arcs and angles. Review on inscribe angles.

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10.4 Other Angle Relationships in Circles

10.4 Other Angle Relationships in Circles. Geometry Fall 2012. Objectives/Assignment. Use angles formed by tangents and chords to solve problems in geometry. Use angles formed by lines that intersect a circle to solve problems. Assignment: pp. 624-625 #2-35. Using Tangents and Chords.

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10.4 Other Angle Relationships in Circles

10.4 Other Angle Relationships in Circles. Geometry Mrs. Spitz Spring 2005. Objectives/Assignment. Use angles formed by tangents and chords to solve problems in geometry. Use angles formed by lines that intersect a circle to solve problems. Assignment: pp. 624-625 #2-35.

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10.4 Other Angle Relationships in Circles

10.4 Other Angle Relationships in Circles. Geometry Mrs. Spitz Spring 2005. Objectives/Assignment. Use angles formed by tangents and chords to solve problems in geometry. Use angles formed by lines that intersect a circle to solve problems. Assignment: pp. 624-625 #2-35.

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10.4 Other Angle Relationships in Circles

10.4 Other Angle Relationships in Circles. Learning Target. I can use theorems about tangents, chords and secants to solve unknown measure of arcs and angles. Review on inscribe angles.

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Bell work 1

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Bell work 1

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10.5 Segment Lengths in Circles

10.5 Segment Lengths in Circles. Geometry Mrs. Spitz Spring 2005. Objectives/Assignment. Find the lengths of segments of chords. Find the lengths of segments of tangents and secants. Assignment: pp. 632-633 #1-30 all. Practice Quiz pg. 635 #1-7 all. Finding the Lengths of Chords.

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10.5 Segment Lengths in Circles

10.5 Segment Lengths in Circles. Geometry Mrs. Spitz Spring 2005. Objectives/Assignment. Find the lengths of segments of chords. Find the lengths of segments of tangents and secants. Assignment: pp. 632-633 #1-30 all. Practice Quiz pg. 635 #1-7 all. Finding the Lengths of Chords.

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10.3 Arcs & Chords

10.3 Arcs & Chords. First & Last Name March 6, 2014 ______Block. The endpoints of a chord are also endpoints of an arc. Theorem 10.2: In a circle or in congruent circles, two minor arcs are congruent if and only if their corresponding chords are congruent. 1. Prove given ? X ,.

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GEOMETRY: Chapter 10

GEOMETRY: Chapter 10. 10.2: Chords#2. Theorem 10.4 In the same circle, or in congruent circles, two minor arcs are congruent if and only if their corresponding chords are congruent. Image taken from: Geometry. McDougal Littell: Boston, 2007. P. 664. Ex.1: Answer:108 o.

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Chapter 10: Area

Chapter 10: Area. 10.2 Areas of Trapezoids, Rhombuses, and Kites. What do you know about a trapezoid?. Theorem 10.4. Area of a Trapezoid The area of a trapezoid is half the product of the height and the sum of the bases. Example 1. Find the area of the trapezoid:. Example 2.

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2001 ? 06 ? 1 ? ? ? ? ????? ???????

M-sequences Decimation of m-sequences. 2001 ? 06 ? 1 ? ? ? ? ????? ???????. Table of Contents. Introduction Decimation of m-sequences Theorem 10.9 There exists m-sequences having same length n Corollary 10.10 We can obtain any m-sequences of length n by suitable decimation

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2.5 Addition and Subtraction Properties

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2.5 Addition and Subtraction

2.5 Addition and Subtraction. Theorem 8: If a segment is added to two congruent segments, then the sums are congruent. Theorem 9: If an angle is added to two congruent angles, then the sums are congruent.

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Theorem

Theorem. The angle subtended by an arc at the centre is double the angle subtended by it at any point on the remaining part of the circle. The three cases. We have to consider three cases When arc PQ is minor arc When arc PQ is a semicircle When arc PQ is major arc. Case-1.

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Regular Languages

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EXAMPLE 5

a. PQRS is inscribed in a circle, so opposite angles are supplementary. a. m Q + m S = 180 o. m P + m R = 180 o. EXAMPLE 5. Use Theorem 10.10. Find the value of each variable. SOLUTION. 75 o + y o = 180 o. 80 o + x o = 180 o. y = 105. x = 100. b.

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