1 / 30

Chemical Kinetics

Chemical Kinetics. Chemical kinetics is the study of time dependence of the change in the concentration of reactants and products.

sela
Télécharger la présentation

Chemical Kinetics

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript


  1. Chemical Kinetics Chemical kinetics is the study of time dependence of the change in the concentration of reactants and products. “The field of chemical kinetics has not yet matured to a point where a set of unifying principles has been identified…There are many different theoretical models for describing how chemical reactions occur.” (M&S, 1137) Generally, we want to understand the rate of reaction: Reactant  Product

  2. Recall from Slide CEq-2… Reactants Products For each constituent…

  3. Rate of reaction, v(t) v(t), the rate of reaction, is defined as the rate of change in ξ(t) with time per unit volume What are units of v(t)? Note all quantities are positive. Examples: 2NO(g) + O2 (g)  2NO2 (g) H2(g) + I2 (g)  2HI (g)

  4. The integrated rate law The rate can be expressed as a function of the reactant concentrations. Most common function is of form: Rate laws must be determined experimentally and, generally, cannot be deduced from the balanced reaction!! General Example 2NO(g) + O2 (g)  2NO2 (g) Determined experimentally! mth order in A nth order in B (m+n)th order overall The Order:

  5. Finding rate laws experimentally There are two common methods for determining rate laws: Method of isolation Set up reaction so one reactant is in excess. Any change in rate will be due to changes in other reactant. Repeat for other reactant. where Method of initial rates Measure concentration change as a function of time, ~v(t), for a series of experimental conditions. (Conditions must include sets where the reactant A has the same initial concentration but B changes and vice versa). EX-CK2

  6. Units of k, rate constant (concentration)n concentration time (concentration)m

  7. Rate laws can be complicated H2(g) + I2 (g)  2HI (g) H2(g) + Br2 (g)  2HBr (g) These rate laws suggest that these two reactions occur via different mechanisms (sets of individual steps). The first may be a elementary reaction (one step) whereas the latter is certainly a multistep process. We will soon explore how to obtain complicated rate laws from suggested mechanisms. EX-CK1

  8. Elementary Rxns vs. Complex Reactions Complex Reactions Elementary Reactions Reactants  Intermediates  Products Reactants  Products Mechanism of a complex reaction is a sequence of elementary reactions. Molecularity of Elementary Reactions: Unimolecular Bimolecular Termolecular

  9. First order reactions The reaction: has rate law: Let’s integrate… Solution: First order reactions decay exponentially.

  10. Ozone decays via first order kinetics k = 1.078 × 10-5 s-1 at 300 K What is slope?

  11. What happens as k increases? k = 0.0125 s-1 k = 0.0250 s-1 k = 0.0500 s-1 k = 0.1000 s-1

  12. Half-life of a first order reaction The half-life, t1/2, is the time it takes to fall to ½ of the starting concentration: Figure 28.3 At ,

  13. Other order reactions… Second order reaction: Second order rate: Integrated rate law: Zero order reaction: Zero order rate: Integrated rate law:

  14. Pseudo-first order reactions You can “overload” the other reactants to determine the order with respect to one individual reactant (method of isolation). For , what happens if [B] >> [A]? Similar to SN2 Lab

  15. Reversible reactions (small DrG) k1 A B k-1 Assume first order, elementary rxn in both directions Rate: Conservation of Mass: Integrate:

  16. At equilibrium k1 A B k-1 At equilibrium… The forward rate equals the reverse at equilibrium. What is the equilibrium constant for this reaction? In terms of rate constants?

  17. Temperature Dependence of k The rate constant can vary in different ways with T. Svante Arrhenius Winner of the 3rd Nobel Prize in Chemistry Differential form of the Arrhenius Equation:

  18. Arrhenius Parameters Integrated forms of Arrhenius equation: Activated (or transition) state Ea is the activation energy. This is the energy required to get over a barrier (at the activated or transition state) between the reactants and products. Ea has units of energy and is T independent. A is the pre-exponential or Arrhenius factor and is T dependent. A is a measure of rate at which collisions occur (and takes lots of things into acct such as orientation, molecular size, number of molecules per volume, molecular velocity, etc). 2HI(g)→I2(g) + H2(g)

  19. Transition-State Theory AB‡ is the transition state (or activated complex.) Transition state theory assumes that the transition state and reactants are in equilibrium with each other, and uses concepts from chemical equilibrium and statistical mechanics to find kinetic info such as rate constants! ‡ Eyring Equation (key to transition-state theory) ‡ From CEq: ‡ Change in Gibbs energy from reactants to TS So… ‡ ‡ ‡ Enthalpy of activation Entropy of activation

  20. Relating Ea to thermodynamics! Necessary Pieces… Arrhenius Equation: Differentiate wrt T: or ‡ From Eyring Equation: van’t Hoff Equation (for Kc): Putting it all together… ‡ ‡ or

  21. What about A, the pre-exponential? ‡ ‡ ‡ ‡ and ‡ ‡ so Unimolecular Gas Phase Reaction ‡ AA‡Products so Same for reactions in solution ‡ ‡ ‡ Bimolecular Gas Phase Reaction ‡ so A+BAB‡Products ‡ What is A?

  22. Transition State Theory and NMR Lab In the NMR/N,N-DMA Paper, Gasparro et al. found an activation energy of 70.3 kJ/mol and a pre-factor of 1.87 × 1010 s-1. Using these values, and a temperature of 298 K, find… ‡ ‡ ‡ Why is TST important? • Provides details of a reaction on the molecular scale. • Connects quantum mechanics and kinetics. • Currently used for many computational studies on reaction rates. EX-CK3

  23. Chapter 29: Reaction Mechanisms

  24. Always remember…. • One can never prove a reaction mechanism, although evidence may disprove a mechanism. • Verifying proposed mechanisms requires extensive experimental verification of each proposed step!

  25. Let’s examine a reaction … Reaction could progress in multiple ways… How can we distinguish? Case 1: One elementary step Case 2: Two step reaction EX-CK4

  26. Now let’s focus on the intermediate… How do k1 and k2 relate in case a? in case b? • I forms quickly but decays slowly… k1 is fast relative to k2. • I builds up to a constant, nearly negligible, concentration until near end of reaction. … k1 is slow relative to k2. Steady state approximation... Valid only if k2 > k1. EX-CK5

  27. Rate Laws do not yield unique mechanisms An empirically determined rate law does not imply a unique reaction mechanism! Consider reaction: Experimentally, it was determined that the rate is given by: Researchers proposed two possible mechanisms. They need to determine if one of them is correct. So how would researchers distinguish between the mechanisms? EX-CK6

  28. Remember the Chain Rxn from CK-6? H2(g) + Br2 (g)  2HBr (g) Proposed Mechanism Initiation: Propagation: Inhibition: Termination: EX-CK7

  29. What about the solution kinetics lab?! • Now that we’ve explored reaction mechanisms and rate laws, let’s try to derive the rate laws from the solution kinetics lab… EX-CK8

  30. Catalysis Catalyst: A substance that participates in the chemical reaction but is not consumed. Provides a new mechanism for reaction and can cause reaction to occur faster. In an experiment involving a catalyst, there are two competing reactions: If both reactions are elementary, overall rate is given by: EX-CK9

More Related