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Engineering Calculation: Torque and Rotation Center Problem Solution

Solve rotational equilibrium problems using torque equations without forces involved. Calculate the weights and angles to determine the rotation center. Utilize trigonometry to find alpha and beam alignment.

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Engineering Calculation: Torque and Rotation Center Problem Solution

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  1. CH12.Problems JH.131

  2. Take the lower center as rotation center then: • M2 (L/4) = M3 (3L/4) M2= 3 M3 • Now the upper center: • M1 (L/4) = (M2+M3) (3 L/4) • M1 = 3(M2+M3) = 3* 4 = 12kg • Only Torques, no forces!

  3. -Ta + Tc cos30 = 0 Tc Sin30 -240 = 0 Only forces no torques

  4. Project! Mg (L/2 sin alpha) is cw torque 2Mg (L) Sin(90-alpha) is CCW torque Then 2 Cos(alpha) = Sin(alpha) /2 Or Tan (alpha) = 4  alpha = 76 deg

  5. Any triangle =180; so, beam makes 60 with vertical

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