1 / 9

Applied Physics and Chemistry

Applied Physics and Chemistry. Gases Lecture 5: Combined Gas Law. Ideal Gas Law. Relates and combines all the other gas laws Mathematical relation of pressure, temperature, volume and the number of moles of a gas PV = nRT R is the universal gas constant. Ideal Gas Constant.

shanta
Télécharger la présentation

Applied Physics and Chemistry

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript


  1. Applied Physics and Chemistry Gases Lecture 5: Combined Gas Law

  2. Ideal Gas Law • Relates and combines all the other gas laws • Mathematical relation of pressure, temperature, volume and the number of moles of a gas • PV = nRT • R is the universal gas constant

  3. Ideal Gas Constant • R= 0.08204784 Latmo/moleK • Watch the units!

  4. Ideal Gas Law • Allows us to find a fourth property if we know 3 of the properties of the gas • Based on experimental measurements • Gas that obeys this law is an ideal gas • Most gases are ideal unless they are at very high pressure or very low temperature

  5. Sample Problem • What is the pressure in atmospheres exerted by 0.500 mole sample of nitrogen gas in a 10.0 L container at 298 K? • Known: V=10.0 L n=0.500 mole T=298 K R=0.08205784 Latmo/moleK • PV=nRT solve for P: P=nRT/V • P=(0.500 mole)(0.08205784 Latmo/moleK)(298K) 10.0 L • P=1.22661816 atmo = 1.23 atmo

  6. Sample Problem • What is the volume of 0.250 mole of oxygen gas at 20.0oC and 0.974 atmo pressure? • Known: 0.250 mole=n T=293.13K P=0.974 atmo R=0.08205784 Latmo/moleK • PV=nRT solve for V: V=nRT/P • V=(0.250 mole)(0.08205784 Latmo/moleK)(293 K) 0.974 atmo • V=6.171187659 L = 6.17 L

  7. Sample Problem • What mass of chlorine gas in grams is contained in a 10.0 L tank at 27oC and 3.50 atmo pressure? • Known: V=10.0L T=300.15 K P=3.50 atmo • PV=nRT n: n=PV/RT • n= (3.50 atmo)(10.0L) (0.08205784 Latmo/moleK)(300.15K) • n = 1.42 mole • Mass: 1.42 mole Cl2 x 70.906 g = 100.7 g • 1 mole

  8. Combined Gas Law • Combines gas laws • PV/T=k • Since we normally compare: • P1V1 = P2V2 T1 T2

  9. Sample Problem • A helium-filled balloon has a volume of 50.0 L at 25oC and 1.08 atmo. What volume will it have at 0.855 atmo and 10oC?

More Related