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Chapter 5 and 6 Handout #4 and #5

Chapter 5 and 6 Handout #4 and #5. 10 of 10. Dr. Clincy Professor of CS. Your next test will cover lectures 27 – 30 and will be held during finals week You should use a calculator You can view the handouts via your laptop or you can print them - you shouldn’t use the browser. Multiplexing.

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Chapter 5 and 6 Handout #4 and #5

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  1. Chapter 5 and 6Handout #4 and #5 10 of 10 Dr. Clincy Professor of CS Your next test will cover lectures 27 – 30 and will be held during finals week You should use a calculator You can view the handouts via your laptop or you can print them - you shouldn’t use the browser Lecture 2

  2. Multiplexing Lecture

  3. Dividing a link into channels – Multiplexing in general Explain this Categories of multiplexing Will also cover Statistical Time-Division Multiplexing Lecture

  4. Frequency-division multiplexing Divide the link’s bandwidth into separate channels (guardband separating each channel) Recall from the Modulation Lectures that – being able to modulate around different “carrier frequencies” was important to being able to adjust the modulated signal into a particular “band” (bandpass signal) On the MULTIPLEXING SIDE Resultant modulated signals are combined into a single composite signal Signals modulate different carrier frequencies (based on amplitude in this case) Lecture

  5. FDM demultiplexing example On the DEMULTIPLEXING SIDE Lecture

  6. Example Assume that a voice channel occupies a bandwidth of 4 kHz. We need to combine three voice channels into a link with a bandwidth of 12 kHz, from 20 to 32 kHz. Show the configuration, using the frequency domain. Assume there are no guard bands. Solution We shift (modulate) each of the three voice channels to different bandwidth. We use the 20- to 24-kHz bandwidth for the first channel, the 24- to 28-kHz bandwidth for the second channel, and the 28- to 32-kHz bandwidth for the third one. Then we combine them into a single composite signal. Lecture

  7. Wavelength-division multiplexing Same as FDM but instead of electrical type signals – muxing optical signals (light signals) Lecture

  8. Time Division Multiplexing (TDM) All networking devices work off clock ticks (explain) Do “tap” analogy Explain this Lecture

  9. Synchronous time-division multiplexing Given n connections needing to be muxed, each frame is divided into n parts (for each slot) Also notice that the time duration before muxing is 1/3 of the time duration after muxing In this case, each frame is divided into 3 time slots For synchronous TDM, the Tx and Rx must be in synch for the Rx to “pull out” of the frame the correct set of data (called interleaving) For synchronous TDM, the data rate of the output link must be n times the data rate of the connection to guarantee the flow of data In keeping the mux and demux in synch, synch bits (framing bits) are added at the beginning of each frame Lecture

  10. Suppose the input data rates are different ? Multilevel multiplexing When input data rates are multiple of others – can be combined to make equal – for example, the two 20 kbps links could be muxed together as a 40 kbps link Multi-slot multiplexing Allocate more than 1 time slot in a frame to a single input – for example, the 50 kbps line gets 2 slots, while the 25 kbps lines get 1 slot each Pulse Stuffing Make the highest input data rate the dominate rate and then add dummy bits (stuffing) to the other input lines Lecture

  11. Statistical TDM For STATISTICAL TDM - Time slots are dynamically allocated based on previous history Slots are reserved – could be wasted slots Slots are allocated to Input Lines with data only – no wasted slots – because of this, theaddressof the Rx has to be carried with the data The address needs to be n bits to define N output lines – with n = log2N (ie. need 5-bit address for 32 output lines) Lecture

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