1 / 14

Understanding Chord and Secant Intersections in Circles

This session explores the properties and calculations related to intersecting chords, secants, and tangents in circles. Learn how to find the measures of angles formed by two chords that intersect inside a circle and those that intersect outside. Through several examples, you'll master the formulas for solving for unknown variables in various scenarios, ensuring a clear understanding of the relationships between segments. This guide includes practice problems to solidify your learning on chord and secant properties.

star
Télécharger la présentation

Understanding Chord and Secant Intersections in Circles

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript

  1. C A B 1 X 222º D Z 55º Session 71 WARM UP 2. Find m1 1. Find mXAB 42º 90º 3. Find mZ 70º

  2. Two chords intersect INSIDE the circle Type 1: a ab = cd d c b

  3. Example 1: 9 12 6 3 x x 2 2 X = 3 X = 8 x 3 6 2 X = 1

  4. 12 2x 8 3x Example 2: Find x 2x  3x = 12  8 6x2 = 96 x2 = 16 x = 4

  5. Two secents intersect OUTSIDE the circle Type 2: E A B C D EA * EB = EC * ED

  6. Example 3: B 13 A 7 E 4 C x D 7 (7 + 13) = 4 (4 + x) x = 31 140 = 16 + 4x 124 = 4x

  7. Example 4: B x A 5 D 8 C 6 E 5 (5 + x) = 6 (6 + 8) x = 11.8 25+5x = 84 59 = 5x

  8. Notice that on the tangent segment, the outside is the whole! Secant Segment External Segment Tangent Segment

  9. Type 2 (with a twist): Secant and Tangent C B E A EA2= EB * EC

  10. Example 5: C B x 12 E 24 A (12 + x) 242 = 12 576 = 144 + 12x x = 36

  11. Example 6: 5 B E 15 C x A (5 + 15) x2 = 5 x2 = 100 x = 10

  12. What you should know by now…

  13. Practice P 220 2-18 even

  14. W.S 10-5

More Related