1 / 12

Fluorescence Resonance Energy Transfer (FRET)

Donor Fluorescence. Acceptor Absorption. INTENSITY. 400. 450. 500. 550. 600. 650. WAVELENGTH (nm). Fluorescence Resonance Energy Transfer (FRET). FRET ( F luorescence R esonance E nergy T ransfer). F örster Equation. S 1. k T = (1/  D )(r/R 0 ) 6. k F. k NR. k T. hv.

sulwyn
Télécharger la présentation

Fluorescence Resonance Energy Transfer (FRET)

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript


  1. Donor Fluorescence Acceptor Absorption INTENSITY 400 450 500 550 600 650 WAVELENGTH (nm) Fluorescence Resonance Energy Transfer (FRET)

  2. FRET(Fluorescence Resonance Energy Transfer) Förster Equation S1 kT = (1/D)(r/R0)6 kF kNR kT hv S0

  3. Efficiency (E) of FRET E = kT/(kT + kD) = R06/(R06 + r6) kD = relaxation rate in the absence of FRET = kF + kNR = 1/Donor or where R0 = 8.79x10-5(2n-4DJ(λ))1/6=distance in Å at which E = 0.5. n = refractive index  1.4 for protein solutions. 2 = orientation factor = 2/3 for an isotropically tumbling system. D = quantum yield of donor. J (λ) = overlap integral between donor emission and acceptor absorption. = εA(λ)•FD(λ)•λ4dλ

  4. D A R 1.0 R0 = 5.3 nm Efficiency INTENSITY 0.5 0 2 4 6 8 10 Distance (nm) 400 450 500 550 600 650 WAVELENGTH (nm) Distance Dependence of FRET Efficiency = 1 – (IDA/ ID) R06 Efficiency = R06 + R6

  5. Distance Dependence of FRET R0 (nm)

  6. Measurement of FRET E can be experimentally measured by looking at changes in the emission lifetime or intensity (quantum yield) of the donor: E = 1 – (DA/D) = 1 – (IDA/ID) Or by looking at the sensitized emission of the acceptor molecule: E = ((IAD/IA) – 1)(A/D)

  7. Upper 50 kDa Subdomain W441F W625F F425W ELC Actin-Binding Cleft V413W ABL W29F W546M W36F W597F Lower 50 kDa Subdomain W512F

  8. H N Donor Acceptor

  9. Title F344W MDE F344Wmant-ATP 22.4 Å Dominguez et al. 1998

  10. ATP ADP F344W-MDE fluorescence emission spectra Normalized fluorescence Wavelength (nm) Wavelength (nm)

  11. R06 Imant Nuct. E = = 1– R06 +R6 INuct. 1.0 R0=20 Å Efficiency 0.5 0 8 16 24 32 40 Distance (Å) ATP ADP Analysis of FRET Data Ro Efficiency (%) r D (% apo) DA (% apo) ADP 81 ± 5 21.4 Å 30 ± 2 Å 6 ± 0.4 76 ± 4 26 ± 2.3 20.1 Å 24 ± 2 Å 76 ± 3 56 ± 4 ATP The nucleotide binding pocket opens ~ 6Å upon phosphate release.

  12. Stopped-flow rates Slope = 3.3 sec-1 μM -1 Max. rate = 150 sec-1 [nucleotide] μM

More Related