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Example Problem: Weak Base. Calculate the pH of a 0.005M solution of Ammonia. 0.005 M ------- 0 M 0 M . I C E. -x ------- +x +x . 0.005-x ------- +x +x . K b =1.8x10 -5 =. Assumption check:.
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Example Problem: Weak Base Calculate the pH of a 0.005M solution of Ammonia 0.005 M ------- 0 M 0 M I C E -x ------- +x +x 0.005-x ------- +x +x Kb=1.8x10-5 = Assumption check:
https://todaysmeet.com/1CBrindley Example Problem Cont.: Weak Base 0.005 M ------- 0 M 0 M I E Kb=1.8x10-5= 0.005-x ------- +x +x Rearranging => x=2.91x10-4 Solve for pH =-log(2.91x10-4)=3.53 10.5