1 / 26

2. Grey Relational Analysis

2. Grey Relational Analysis. x. x 1. x 2. x 3. k. 2.1: Grey Relational Analysis. x 0 ={ x 0 (1), x 0 (2),…, x 0 ( n )}: reference sequence x i ={ x i (1), x i (2),…, x i ( n )}: comparative sequence i = 1,2,…, m . Grey relational coefficient : ( x 0 ( k ) , x i ( k ) )

Télécharger la présentation

2. Grey Relational Analysis

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript


  1. 2. Grey Relational Analysis x x1 x2 x3 k

  2. 2.1: Grey Relational Analysis • x0={x0(1), x0(2),…, x0(n)}: reference sequence • xi={xi(1), xi(2),…, xi(n)}: comparative sequence i = 1,2,…,m. • Grey relational coefficient: (x0(k), xi(k)) (x0(k), xi(k)) = [min+max]  [0i(k)+max] 0i(k)=x0(k)  xi(k), : distinguish coefficient max=maxi maxkx0(k)  xi(k), 0    1, min=mini minkx0(k)  xi(k).

  3. Grey Relational Analysis • Grey relational grade: (x0, xi) • 0  (x0(k), xi(k))  1. • 0  (x0, xi)  1. • Describes the posture relationships between one main factor (reference series) and all other factors (comparison series) in a given system.

  4. Axioms of GRA • Norm Interval (x0(k), xi(k))(0,1], k. (x0(k), xi(k)) = 1, iff x0(k) =xi(k), k. (x0(k), xi(k)) = 1, iff x0,xi . • Duality Symmetric (x0(k), xi(k)) = (xi(k), x0(k)) , iff X = {x0,xi}.

  5. Axioms of GRA • Wholeness (x0(k), xi(k))  (xi(k), x0(k)) almost always, iff X = {xj j = 0,1,…,m, m  2}. • Approachability (x0(k), xi(k)) decreases along with (k) increasing,where (k) = [(x0(k)  xi(k))2]1/2 =x0(k)  xi(k).

  6. 2.2: Grey Generating Space Based on the concept and generating schemes of grey system theory, thedisorderly raw data can • be turned to a regular series for grey modeling. • be transferred to a dimensionless series for grey analyzing. • be changed into a unidirectional series for decision making.

  7. 灰關聯因子集 • 假設 X 為序列 xi = {xi(1), xi(2),…, xi(n)}, 其中i = 1,2,…, m, 所構成之集合。 • 若P(X)為一灰關聯因子集,則 xi P(X) 。 • 為使序列具有可以比較之特性,以利灰關聯分析的進行,則序列 xi必須滿足下列三個條件: • 無因次性(Normalization):不論因子xi(k)之測度單位為何,必須經過處理使其成為無因次性(去除單位)。 • 同等級性(Scaling):各序列xi中之xi(k)值均屬同等級或等級相差不大(等級相差不超過2)。 • 同級性(Polarization):序列中的因子描述應為同方向。

  8. Grey Generating Operations An original sequencex= {x(1), x(2),…, x(n)} The generating sequence y= {y(1), y(2),…, y(n)} • Initializing operation: y(k) = x(k)  x(1) • Averaging operation: y(k) = x(k)  xave, • Maximizing operation: y(k) = x(k)  xmax • Minimizing operation: y(k) = x(k)  xmin • Intervalizing operation: y(k) = [x(k) xmin]  [xmax xmin]

  9. Example 2.1 • x= {4, 2, 6, 8}; xave= 5, xmax= 8, xmin= 2.

  10. Accumulated Generating Operation (AGO) An original sequence x(0)={x(0)(1), x(0)(2),…, x(0)(n)}, x(0)(k) ≧0. • The 1st order AGO (1-AGO): AGO•x(0) = x(1) • The jth order AGO (j-AGO):

  11. Inverse AGO (IAGO) (0)(x(r)(k)) = x(r)(k). (1)(x(r)(k)) = (0)(x(r)(k))  (0)(x(r)(k1)). ( j)(x(r)(k)) = ( j1)(x(r)(k))  ( j1)(x(r)(k1)). • IAGO•x(1) = x(0) = (1)(x(1)) • x(0)(1) = x(1)(1),x(0)(k) = x(1)(k) x(1)(k1) , k=2,3,…,n • Mean generating operation: z(1)(k) =0.5[ x(1)(k) + x(1)(k1)], k=2,3,…,n

  12. x(0)(k) x(1)(k) 7.5 3 4.5 2 3 1 2 1 3 4 k 1 k 1 2 3 4 Example 2.2 • x(0)={x(0)(1), x(0)(2), x(0)(3), x(0)(4)}={1,2,1.5,3} • x(1)={x(1)(1), x(1)(2), x(1)(3), x(1)(4)}={1,3,4.5,7.5}

  13. AGO Effect • The non-negative, smooth, discrete function can be transferred into a series, extended according to an approximate exponential law (grey exponential law). • Thedisorderly raw data can be turned to a regular series for grey modeling.

  14. Example 2.3

  15. Weather Analysis

  16. Weather Analysis Step 1: Data Processing – Initializing 降雨量: x0={1,1.176,1.457,1.151,1.575,1.738,1.135,1.608,2.118,1.425,1.077,0.824} 降雨天數: x1={1,0.938,1,0.813,0.938,0.813,0.500,0.625,0.750,0.750,0.875,0.875} 平均氣溫: x2={1,1.020,1.154,1.423,1.651,1.805,1.940,1.926,1.805,1.597,1.369,1.128} 相對濕度: x3={1,1.024,1.024,1.012,1.012,1.012,0.963,0.963,0.963,0.851,0.963,0.988}

  17. Weather Analysis

  18. Weather Analysis Step 2: Compute0i(k)=x0(k) xi(k) and then Find maxandmin 01={0,0.238,0.457,0.338,0.638,0.926,0.635,0.983,1.368,0.675,0.202,0.051} 02={0,0.156,0.303,0.272,0.076,0.067,0.805,0.318,0.313,0.173,0.293,0.303} 03={0,0.152,0.433,0.139,0.563,0.726,0.172,0.645,1.155,0.473,0.113,0.164}  max=1.368, min=0

  19. Weather Analysis Step 3: Find the Grey Relational Coefficients Let =0.5

  20. Weather Analysis Step 4: Calculate the Grey Relational Grades Average the grey relational coefficients then r(x0,x1)=0.619, r(x0,x2)=0.755, r(x0,x3)=0.687 Step 5: Sort the Grey Relational Grades r(x0,x2) r(x0,x3)  r(x0,x1) Note: x0=降雨量, x1=降雨天數,x2=平均氣溫, x3=相對濕度

  21. Example 2.4 Data Pre-processing: x1 = {1.0000, 1.0000, 1.0000, 1.0000} x2 = {1.1759, 0.9375, 1.0201, 1.0244} x3 = {1.4572, 1.0000, 1.1544, 1.0244} x4 = {1.1509, 0.8125, 1.4228, 1.0122}

  22. Weather Analysis 2

  23. Weather Analysis 2 Grey Relational Coefficients:  = 0.8 r12 = 0.8537, r21 =0.8388 Among four months, January and February are very alike. In general, rij  rji

  24. Multi-Reference Sequences Reference sequences: yi={yi(1), yi(2),…, yi(n)} Comparison sequence: xj={xj(1), xj(2),…, xi(n)} i=1,2,…,p; j=1,2,…,q. • Grey relational coefficient: (yi(k), xj(k)) (yi(k), xj(k)) = [min+max]  [ij(k)+max] ij(k) =yi(k)  xj(k), : distinguish coefficient max=maxi maxj maxk ij(k), 0    1, min=mini minj mink ij(k). • Grey Relational Grade: (yi, xj)

  25. Example 2.5 Data Pre-processing: x1 = {1, 0.889, 0.865, 0.849}  y1 x2 = {1, 1.010, 1.017, 1.027}  y2 x3 = {1, 0.990, 1.086, 1.042} x4 = {1, 1.529, 1.467, 1.510}

  26. Numerical Example Compute0i(k): 13={0, 0.101, 0.221, 0.193}; 14={0, 0.640, 0.602, 0.661} 23={0, 0.020, 0.067, 0.015}; 24={0, 0.519, 0.450, 0.483}  max = 0.661, min = 0. If  = 0.5, then • (y2, x3) = 0.932最大,故運輸業x3對工業y2之影響最大。 • ,最強參考列y2 。 • ,最強比較列x3 。

More Related