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chemical equilibrium!. First, a metaphor:. Two floors of a store are connected by up and down escalators. Floor 1 has 7 people, floor 2 has 12 people. There are always 2 people occupying each escalator. Floor 2: 7 people. Floor 1: 12 people. Floor 2: 7 people. 2 people

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## chemical equilibrium!

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**chemical**equilibrium!**First, a metaphor:**Two floors of a store are connected by up and down escalators Floor 1 has 7 people, floor 2 has 12 people. There are always 2 people occupying each escalator**Floor 2: 7 people**Floor 1: 12 people**Floor 2: 7 people**2 people on the up escalator Floor 1: 12 people 2 people on down escalator**Floor 2: 7 people**2 people on the up escalator Floor 1: 12 people 2 people on down escalator Question 1: if there are always two people on each escalator at any one moment, will the amount of people on each floor ever change?**Floor 2: 7 people**2 people on the up escalator Floor 1: 12 people 2 people on down escalator Question 2: if there are always two people on each escalator at any one moment, will the specific people occupying each floor ever change?**N2 + 3H2 2NH3**The double arrow tells us that this reaction can go in both directions:**N2 + 3H2 2NH3**1) Reactants react to become products, N2 + 3H2 2NH3 (‘forward’ reaction)**N2 + 3H2 2NH3**1) Reactants react to become products, N2 + 3H2 2NH3 (‘forward’ reaction) while simultaneously, 2) Products react to become reactants N2 + 3H2 2NH3 (‘reverse’ reaction)**N2 + 3H2 2NH3**In a closed system, where no reactants, products, or energy can be added to or removed from the reaction, a reversible reaction will reach equilibrium.**N2 + 3H2 2NH3**At equilibrium, the rateof the forward reaction becomes equal to the rate of the reverse reaction, and so, like our escalator metaphor, the two sides, reactants and products, will have constant amounts, even though the reactions continue to occur.**N2 + 3H2 2NH3**However (like the metaphor), the equilibrium amounts of reactants and products are usually not equal, they just remain unchanged.**reverse**forward**reverse**forward**reverse**forward**reverse**forward**reverse**forward**reverse**forward**reverse**forward**reverse**forward**reverse**forward**reverse**forward**reverse**forward etc! the reactions go on continuously in both directions.**Changes in the concentrations**of the reactants and products can be graphed; the graph indicates when equilibrium has been reached. concentration time**For N2 + 3H2 2NH3,**suppose you begin with the following: N2 = 1 M, H2 = 1 M, and NH3 = 0 M concentration time**For N2 + 3H2 2NH3,**suppose you begin with the following: N2 = 1 M, H2 = 1 M, andNH3 = 0 M concentration time**For N2 + 3H2 2NH3,**suppose you begin with the following: N2 = 1 M, H2 = 1 M, andNH3 = 0 M concentration time**For N2 + 3H2 2NH3,**suppose you begin with the following: N2 = 1 M, H2 = 1 M, andNH3 = 0 M concentration time**For N2 + 3H2 2NH3,**suppose you begin with the following: N2 = 1 M, H2 = 1 M, andNH3 = 0 M concentration time**For N2 + 3H2 2NH3,**suppose you begin with the following: N2 = 1 M, H2 = 1 M, andNH3 = 0 M concentration time**For N2 + 3H2 2NH3,**suppose you begin with the following: N2 = 1 M, H2 = 1 M, andNH3 = 0 M concentration time**For N2 + 3H2 2NH3,**suppose you begin with the following: N2 = 1 M, H2 = 1 M, andNH3 = 0 M concentration time**For N2 + 3H2 2NH3,**suppose you begin with the following: N2 = 1 M, H2 = 1 M, andNH3 = 0 M concentration time**For N2 + 3H2 2NH3,**suppose you begin with the following: N2 = 1 M, H2 = 1 M, andNH3 = 0 M concentration time**For N2 + 3H2 2NH3,**suppose you begin with the following: N2 = 1 M, H2 = 1 M, andNH3 = 0 M concentration time**For N2 + 3H2 2NH3,**suppose you begin with the following: N2 = 1 M, H2 = 1 M, andNH3 = 0 M concentration time**For N2 + 3H2 2NH3,**suppose you begin with the following: N2 = 1 M, H2 = 1 M, andNH3 = 0 M concentration time

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