1 / 11

Animating the Correcting Algorithm: A Step-by-Step Example

This presentation illustrates the correcting algorithm with an example. It explains how to identify and handle violating arcs in a network flow problem using distance labels. The generic step involves checking if an arc (i, j) is violating based on distance labels d(i) and d(j) compared to the cost of the arc. The animation will guide you through the process of replacing the distance label d(j) with the value calculated from d(i) and the arc cost, emphasizing the dynamics of the algorithm.

tevy
Télécharger la présentation

Animating the Correcting Algorithm: A Step-by-Step Example

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript

  1. OPIM 915 -- #7Animation Label Correcting Algorithm

  2. An Example   2 4 2 3 3 3 1   -2 6 1 5 7 0 Initialize 2 3 4 3 d(1) := 0; d(j) :=  for j  1 -4 3 6   In next slides: the number inside the node will be d(j). Violating arcs will be in thick lines.

  3. An Example 2  3  3 3 3 1 -2 6 0   Generic Step 2 3 4 3 An arc (i,j) is violating if d(j) > d(i) + cij. -4   Pick a violating arc (i,j) and replace d(j) by d(i) + cij.

  4. An Example 2  3  3 3 3 1 -2 6 0  6  Generic Step 2 3 4 3 An arc (i,j) is violating if d(j) > d(i) + cij. -4   Pick a violating arc (i,j) and replace d(j) by d(i) + cij.

  5. An Example 2  3  3 3 3 1 -2 6 0 6   Generic Step 2 3 4 3 An arc (i,j) is violating if d(j) > d(i) + cij. -4  3  Pick a violating arc (i,j) and replace d(j) by d(i) + cij.

  6. An Example 2  5  3 3 3 3 1 -2 6 0 6   Generic Step 2 3 4 3 An arc (i,j) is violating if d(j) > d(i) + cij. -4 3   Pick a violating arc (i,j) and replace d(j) by d(i) + cij.

  7. An Example 2 5  3  3 3 3 1 -2 6 0  4 6  Generic Step 2 3 4 3 An arc (i,j) is violating if d(j) > d(i) + cij. -4 3   Pick a violating arc (i,j) and replace d(j) by d(i) + cij.

  8. An Example 2 5  3  3 3 3 1 -2 6 0 6 4   Generic Step 2 3 4 3 An arc (i,j) is violating if d(j) > d(i) + cij. -4 3   6 Pick a violating arc (i,j) and replace d(j) by d(i) + cij.

  9. An Example 2 5  3  3 3 3 1 -2 6 0 6  4  Generic Step 2 3 4 3 An arc (i,j) is violating if d(j) > d(i) + cij. -4 3  2  6 Pick a violating arc (i,j) and replace d(j) by d(i) + cij.

  10. An Example 2 5  3  3 3 3 1 -2 6 0  6 4 9  Generic Step 2 3 4 3 An arc (i,j) is violating if d(j) > d(i) + cij. -4 3 2   6 Pick a violating arc (i,j) and replace d(j) by d(i) + cij.

  11. An Example 2 5  3  3 3 3 1 -2 6 0 4  6  9 Generic Step 2 3 4 3 An arc (i,j) is violating if d(j) > d(i) + cij. -4 2  3 6  Pick a violating arc (i,j) and replace d(j) by d(i) + cij. No arc is violating We now show the predecessor arcs. The distance labels are optimal

More Related