1 / 16

Chemical Reactions

Chemical Reactions. Chapter 10 Reactions and Equations. Evidence of Chemical Reactions. How many indicators of a chemical reaction can you list? 1. 2. 3. 4. 5. ANSWERS. Temperature change Color change Texture change Precipitate formation Bubbling, fizzing

thom
Télécharger la présentation

Chemical Reactions

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript

  1. Chemical Reactions Chapter 10 Reactions and Equations

  2. Evidence of Chemical Reactions • How many indicators of a chemical reaction can you list? 1. 2. 3. 4. 5.

  3. ANSWERS • Temperature change • Color change • Texture change • Precipitate formation • Bubbling, fizzing • Gas released

  4. Representing Chemical Reactions • Chemical equations show REACTANTS on the left and PRODUCTS on the right side of an arrow. Reactant 1 + Reactant 2 → Product 1 + Product 2

  5. A skeletal equation uses chemical formulas rather than words to identify the reactants and the products. For example, the skeleton equation for the reaction between iron and chlorine is represented below. • Iron(s) + chlorine(g) → iron (III) chloride (s) • Fe(s) + Cl2 (g) → FeCl3(s) One iron atom One iron atom Two chlorine atoms Three chlorine atoms

  6. Practice Problems • Write skeleton equations for each word equation on page 279 of text.

  7. Answers • H2 (g) + Br2(g) → 2HBr (g) • 2CO(g) + O2(g) → 2CO2 (g) • 2KClO3(s) → 2KCl(s) + 3O2(g)

  8. Balancing Equations Fe(s) + Cl2 (g) → FeCl3(s) One iron atom One iron atom Two chlorine atoms Three chlorine atoms To accurately represent a chemical reaction by an equation, the equation must show how the law of conservation of mass is obeyed. The equation must show that the number of atoms of each reactant and each product is equal on both sides of the arrow.

  9. Cl +→ + → → 2 iron atoms 6 chlorine atoms 2 iron atoms, 6 chlorine atoms Cl Cl Cl Fe Fe Cl Cl Cl Cl Cl Cl Cl Cl Cl Fe Fe Cl

  10. Steps for balancing equations • Write the skeleton equation for the reaction. • Count the atoms of the elements in the reactants. • Count the atoms of the elements in the products. • Change the coefficients to make the number of atoms of each element equal on both sides of the equation.

  11. NEVER CHANGE THE SUBSCRIPT in a chemical formula to balance an equation because doing so changes the identity of the substance. • Write the coefficients in their lowest possible ratio. • CHECK YOUR WORK! Make sure that the chemical formulas are written correctly. Then check that the number of atoms of each element is equal on both sides of the equation.

  12. Practice Problems • Write chemical equations for each of the word equations on page 282 of text. • In water, iron (III) chloride reacts with sodium hydroxide , producing solid iron (III) hydroxide and sodium chloride. • Liquid carbon disulfide reacts with oxygen gas, producing carbon dioxide gas and sulfur dioxide gas.

  13. 6. Solid zinc and aqueous hydrogen sulfate react to produce hydrogen gas and aqueous zinc sulfate.

  14. ANSWERS • FeCl3 (aq) + NaOH(aq) → Fe(OH)3 (s) + NaCl(s) • CS2(l) + O2(g) → CO2(g) + SO2 (g) • Zn(S) + H2SO4 (aq) → H2 (g) + ZnSO4(aq)

  15. Did you balance? FeCl3 (aq) + NaOH(aq) → 3Fe(OH)3 (s) + 3NaCl(s) CS2(l) + 3O2(g) → CO2(g) + 2SO2 (g) Zn(S) + H2SO4 (aq) → H2 (g) + ZnSO4(aq) (already balanced)

  16. Symbols → yields, produces, makes, forms, etc. • Solid • Liquid (aq) aqueous (g) gas, also may appear as ↑ ↔ equilibrium, (reaction can also go in reverse) You may also see this as → ←

More Related