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WS: Bonds and Valence Electrons

WS: Bonds and Valence Electrons. As: -3, 3, and 5 (1 pt) Au: 3 and 1 % Ionic Character Type of Bond SO 2 : 19% Covalent MgCl 2 : 59% Ionic AgCl: 30% Covalent (2 points each) Total for assignment is 8 points. Lecture: Formula Weight.

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WS: Bonds and Valence Electrons

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  1. WS: Bonds and Valence Electrons • As: -3, 3, and 5 (1 pt) • Au: 3 and 1 % Ionic Character Type of Bond • SO2: 19% Covalent • MgCl2: 59% Ionic • AgCl: 30% Covalent (2 points each) Total for assignment is 8 points.

  2. Lecture: Formula Weight

  3. Formula Weight is the total mass of a compound.FW = SUM(Atomic Mass x # of the Element)

  4. Calculating the Formula Weight of H2SO4 Step 1: Break the formula down into the elements that make it up. H S O

  5. Calculating the Formula Weight of H2SO4 Step 2: Place the number of each element that make the compound. H: 2 S: 1 O: 4

  6. Calculating the Formula Weight of H2SO4 Step 3: Multiply each number by the Atomic Mass for each element. H: 2 x 1.00794 = 2.01588 S: 1 x 32.065 =32.065 O: 4 x 15.9994 =63.9976

  7. Calculating the Formula Weight of H2SO4 Step 4: Total the mass for all the elements. H: 2 x 1.00794 = 2.01588 S: 1 x 32.065 = 32.065 O: 4 x 15.9994 = 63.9976 98.07848

  8. Calculating the Formula Weight of H2SO4 Step 5: Round the answer to the least Significant Figures(S.F’s). To find the least Significant Figure (S.F’s) you have to go back to the atomic masses. H: 2 x 1.00794 = 2.01588 (6 S.F’s) S: 1 x 32.065 =32.065 (5 S.F’s) O: 4 x 15.9994 =63.9976 (6 S.F’s) 98.07848 Your final answer can only have 5 figures

  9. Calculating the Formula Weight of H2SO4 Step 6: Round your answer and add units to the end of your answer. H: 2 x 1.00794 = 2.01588 (6 S.F’s) S: 1 x 32.065 =32.065 (5 S.F’s) O: 4 x 15.9994 =63.9976 (6 S.F’s) 98.07848 98.07848 rounds to 98.078 g/mole F.W. of H2SO4=98.078 g/mole

  10. Calculating the FW of Ca(OH)2 Ca: O: H:

  11. Calculating the FW of Ca(OH)2 Ca: 1 O: 2 H: 2

  12. Calculating the FW of Ca(OH)2 Ca: 1 x 40.078 O: 2 x 15.9994 H: 2 x 1.00794

  13. Calculating the FW of Ca(OH)2 Ca: 1 x 40.078 = 40.078 O: 2 x 15.9994 = 31.9988 H: 2 x 1.00794 = 2.01588

  14. Calculating the Formula Weight of Ca(OH)2 Ca: 1 x 40.078 =40.078 O: 2 x 15.9994 =31.9988 H: 2 x 1.00794 = 2.01588 =74.09268 Your final answer should have 5 significant figures.

  15. Calculating the Formula Weight of Ca(OH)2 FW for Ca(OH)2 = 74.093 g/mole

  16. Calculate the formula weight for the compound CaCl2.

  17. Calculate the formula weight for the compound CaCl2. Ca: 1 x 40.078 =40.078 Cl: 2 x 35.453 =70.906 =110.984 F.W.=110.98 g/mole

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