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AND Types of Reactions Let the fun begin!

balancing equations. AND Types of Reactions Let the fun begin!. Why do we need to balance equations? To satisfy the Law of Conservation of Mass. Which says: Matter cannot be created or destroyed; therefore,

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AND Types of Reactions Let the fun begin!

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  1. balancing equations AND Types of Reactions Let the fun begin!

  2. Why do we need to balance equations? To satisfy the Law of Conservation of Mass Which says: Matter cannot be created or destroyed; therefore, You must have the same number of atoms on each side of a chemical equation to show conservation of mass. ie. Reactants = Products

  3. Step 1 • Make sure compounds are balanced; In this reaction, the reactant compounds’ charges are not balanced: Na+1O-2 + Ba+2Cl-1 --- Na+1Cl-1 + Ba+2O-2 Use subscripts to balance the compounds to zero: Na2O + BaCl2 -NaCl + BaO (+2)+(-2) = 0 ( +2)(-2) = 0

  4. Step 2 • Use coefficients to balance the numbers of atoms on each side; Na2O + BaCl2 -NaCl + BaO How many sodiums on the left? 2; how many on the right/ 1; put a coefficient 2 in front of the one on the right. How many oxygens on the left/ on the right/, etc. Na2O + BaCl2 -2NaCl + BaO

  5. Step 3:Check to Insure the same number of atoms on both sides Na2O + BaCl2 -2NaCl + BaO • Atom Left Right • Na 2 2 • O 1 1 • Ba 1 1 • Cl 2 2 • Balanced! Mother Nature would be proud! • Great job!

  6. Let’s Practice!Balance this equation: Al + CuCl2 --- AlCl3 + Cu How many aluminum atoms on the left? On the right? How many copper atoms on the left? On the right? How many chlorine atoms on the left? On the right? Use coefficients to balance each atom!

  7. Answer: 2Al + 3CuCl2 --- 2AlCl3 + 3Cu

  8. Balance this equation: Na3PO4 + CuSO4 - Na2SO4 + Cu3(PO4)2

  9. Answer: Na3PO4 + CuSO4 - Na2SO4 + Cu3(PO4)2 First ask, “how many sodiums on the left, how many sodiums on the right?” Use coefficients to balance each of the atoms left to right. 2Na3PO4 + 3CuSO4 -- 3Na2SO4 + Cu3(PO4)2

  10. Balance this equation: C4H10 + O2 --- CO2 + H2O + E

  11. Answer: C4H10 + 6.5O2 --- 4CO2 + 5H2O + E

  12. What does it really look like on a molecular level? N2 + H2 --- NH3

  13. The molecules would look like this: N2 + H2 NH3

  14. If the equation is balanced? • You need to show the same number of atoms on each side of the arrow: • N2 + 3H2 2 NH3

  15. Practice More! • Try this helpful link: • http://newtraditions.chem.wisc.edu/FPTS/fbeqns/chemeqnf.htm

  16. Types of ReactionsWhy? They help you predict products. Synthesis (direct combination) Decomposition Single Replacement Double Replacement Combustion Acid Base Neutralization

  17. Synthesis (direct combination) A + B  AB

  18. Decomposition AB  A + B

  19. Single Replacement ABaq + Cs CBaq + As

  20. Double Replacement ABaq + CDaq CBs + ADaq

  21. Combustion CxHx + O2 CO2 + H2O + E (hydrocarbon)

  22. Acid Base Neutralization Acid + Base  Salt + Water HA + BOH  BA + H2O

  23. Balancing Equations:HOT or NOT?

  24. Definitely HOT!

  25. The End … of this slide show, but just the beginning of more chemistry (and the Red Sox Dynasty)!

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