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Hermitian Operators. To every Hermitian operator , there exists (ATLEAST) one basis consisting of orthogonal eigenvectors, It is diagonal in this eigen basis & has eigen values as its diagonal entries. Before we prove that lets prove another theorem
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Hermitian Operators • To every Hermitian operator , there exists (ATLEAST) one basis consisting of orthogonal eigenvectors, It is diagonal in this eigen basis & has eigen values as its diagonal entries. • Before we prove that lets prove another theorem • If |V = 0 implies |V = 0 then -1 exists राघववर्मा
Hermitian Operators (Contd…) राघववर्मा
Now the theorem Did not know how to make a box submatrix. Here it is the submatrix 22…. 2n n2 …. nn राघववर्मा
The diagonalisation of a Hermitian matrix (contd..) राघववर्मा
In Absence of Degeneracy राघववर्मा
An example राघववर्मा