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Specific Heat

Specific Heat. Specific Heat. Specific heat is the amount of heat needed to raise the temperature of 1 g of a substance by 1 °C (or K) is different for different substances in the SI system has units of J/g C in the metric system has units of cal/g C. Examples of Specific Heats.

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Specific Heat

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  1. Specific Heat

  2. Specific Heat Specific heat • is the amount of heat needed to raise the temperature of 1 g of a substance by 1 °C (or K) • is different for different substances • in the SI system has units of J/g C • in the metric system has units of cal/g C

  3. Examples of Specific Heats

  4. Learning Check A. For the same amount of heat added, a substance with a large specific heat 1) has a smaller increase in temperature 2) has a greater increase in temperature B. When ocean water cools, the surrounding air 1) cools 2) warms 3) stays the same C. Sand in the desert is hot in the day and cool at night. Sand must have a 1) high specific heat 2) low specific heat

  5. Solution A. For the same amount of heat added, a substance with a large specific heat 2) has a smaller increase in temperature B. When ocean water cools, the surrounding air 2) warms C. Sand in the desert is hot in the day and cool at night. Sand must have a 2) low specific heat

  6. Heat Equation Rearranging the specific heat expression gives the heat equation. energy = specific heat x mass x change in temperature heat = c x m x ΔT Units: • Energy Joules (J) or calories (cal) • Mass  grams (g) or kilograms (kg) • Temperature change  °C or °F or K • Specific heat cal/g•°C or J/g•°C

  7. Sample Calculation for Heat A hot-water bottle contains 750 g of water at 65 °C. Water has a specific heat of 1.00 cal/g • °C. If the water cools to body temperature (37 °C), how many calories of heat could be transferred to sore muscles? STEP 1  Write the version of the formula needed. energy = c x m x ΔT STEP 2 Plug in given values energy = 1.00 cal x 750 g x (65 °C - 37 °C) g • °C

  8. Sample Calculation for Heat STEP 3  Solve energy = 1.00 cal x 750 g x (65 °C - 37 °C) g • °C energy = 1.00 cal x 750 g x (28 °C) g • °C energy = 21,000 calories

  9. Example of Calculating Specific Heat What is the specific heat of a metal if 24.8 g absorbs 65.7 cal of energy and the temperature rises from 20.2 C to 24.5 C? STEP 1  Write the version of the formula needed. energy = c x m x ΔT energy = c m x ΔT

  10. Example of Calculating Specific Heat What is the specific heat of a metal if 24.8 g absorbs 65.7 cal of energy and the temperature rises from 20.2 C to 24.5 C? STEP 2 Plug in given values energy = c m x ΔT ________65.7 cal_________ = c 24.8 g x (24.5°C to 20.2°C)

  11. STEP 3  Solve ________65.7 cal_______ = c 24.8 g x (24.5°C to 20.2°C) ___65.7 cal____ = c 24.8 g x (4.3°C) __65.7 cal__ = c 106.64 g • °C __0.62 cal__ = c c = 0.62 cal/g • °C g • °C

  12. Learning Check How many kilojoules are needed to raise the temperature of 325 g of water from 15.0 °C to 77.0 °C? 1) 20.2 kJ 2) 84.3 kJ 3) 105 kJ 84.3 kJ

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