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Dr. Ali Tayeh First Semester 2009. Design of Concrete Structure I. Lecture 3. Loads ACI 318-05. Dead Load (Slab & Beam). Concrete structural system. Dead Load (Slab & Beam). Slab types Solid slab One-way slab Two way slab Ribbed Slab one way or two way according to rib system.

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## Design of Concrete Structure I

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**Dr. Ali**Tayeh First Semester 2009 Design of Concrete Structure I**Lecture 3**Loads ACI 318-05**Dead Load (Slab & Beam)**Concrete structural system**Dead Load (Slab & Beam)**Slab types Solid slab • One-way slab • Two way slab Ribbed Slab • one way or two way according to rib system The effect of slab type Oneway slab Two-way slab**Solid slab**Two way slab One-way slab Ribbed Slab Two way slab One-way slab**Dead Load (Slab own weight ) assume depth 30 cm(22cm block**+8cm concrete) Geometry of rib in one way ribbed slab**Dead Load (Slab own weight ) assume depth 30 cm(22cm block**+8cm concrete) • Own weight of slab • From geometry of rib as shown • - Total volume of rib (hatched) = 0.55 x 0.3 x 0.25 = 0.04125 m3 • - Volume of hollow block = 0.4x0.25x0.22= 0.022 m3 • - Concrete density = 25 KN/m3. • - Net concrete volume = 0.04125 – 0.022 = 0.01925 m3 • - Weight of concrete = 0.01925 x 25 = 0.48125 KN • - Weight of concrete /m2 = • - Weight of hollow block /m2 = • - Total Own weight=3.5+1.6=5.1 KN/m2**Dead Load (Covering Material)**• Covering materials • - Plaster coat density = 21 KN / m3, thickness = 0.02 m • - Weight of plaster / m2 = 21x 0.02 = 0.42 KN/m2 • - Sand density = 18 KN / m3, thickness = 0.08 m • - Weight of sand / m2 = 18 x 0.08 = 1.44 KN/m2 • - Mortar density = 21 KN / m3, thickness = 0.025 m • - Weight of mortar / m2 = 21 x 0.025 = 0.525 KN/m2 • - Tiling density = 22 KN / m3, thickness = 0.025 m • - Weight of tiling / m2 = 22 x 0.025 = 0.55 KN/m2 • Total Weight of covering materials • =0.42+1.44+0.525+0.55=2.94 KN/m2**Dead Load (Walls)**• Partition load = 2.5 KN/m2 • Total weight/ m2 • = Total Own weight + Total Weight of covering materials • = 5.1+2.94+2.5= 10.6 KN/m2 • Service live load = 4 KN/m2 According to (ASCE7-05 Table 4-1)**3 m**1 m**Astructural Design code**Astructural Design codeis a code that involves the design of a certain type of structures (reinforced concrete, structural steel, etc.). The structural code that will be used extensively throughout this course is The American concrete Institute (ACI-318-05) , which is one of the most solid codes due to its continuing modification, improvement, and revision to incorporate the latest advancements in the field of reinforced concrete design and construction.**Design Methods**The Ultimate – Strength Design Method • At the present time, the ultimate-strength design method is the method adopted by most prestigious design codes • In this method, members are designed such that the internal forces in the members produced by factored loads do not exceed the corresponding strength capacities and allowing for some capacity reduction.**The Working-Stress Design Method**• Before the introduction of the strength-design method in the ACI building code in 1956, the working stress design method was used in design. • This method is based on the condition that the stresses caused by service loads without load factors are not to exceed the allowable stresses which are taken as a fraction of the ultimate stresses of the materials, for concrete and for steel**Load Factors**In this course, we will us this load factorU =1.2 D + 1.6 L

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