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Honors Precalculus. Day 1 Section 4.1. One-to-One Functions Will pass both the vertical and horizontal line tests Are either always increasing or always decreasing Inverse functions The inverse of f (x) is written as f -1 (x). f (x) and f - 1 (x) will undo one-another, meaning

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## Honors Precalculus

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**Honors Precalculus**Day 1 Section 4.1 Perkins**One-to-One Functions**Will pass both the vertical and horizontal line tests Are either always increasing or always decreasing Inverse functions The inverse of f(x) is written as f -1(x). f(x) and f -1(x) will undo one-another, meaning Only 1-to-1 functions can have inverses (which will require us to limit the domain of those which are not). The domain of f(x) is the same as the range of f -1(x). The range of f(x) is the same as the domain of f -1(x). f(x) and f -1(x) are symmetric about the line y = x. To find f -1(x): Swap x and y. Solve for y.**6**4 2 5 10 -2 -4 -6 Which of these functions are 1-to-1? (not a function)**1. Sketch the graph of the inverse of this 1-to-1 function.**Show that these functions are inverses of each other. Method 1: Method 2: graph and look for symmetry about y = x.**3. is a 1-to-1 function. Find its**inverse. Swap variables. Solve for y.**4. Give the domain of f(x) and use f -1(x) to find its**range. f(x) is 1-to-1.**Honors Precalculus**Day 1 Section 4.1 Perkins**One-to-One Functions**Inverse functions To find f -1(x):**6**4 2 5 10 -2 -4 -6 Which of these functions are 1-to-1?**1. Sketch the graph of the inverse of this 1-to-1 function.**Show that these functions are inverses of each other. Method 1: Method 2:**3. is a 1-to-1 function. Find its**inverse.**4. Give the domain of f(x) and use f -1(x) to find its**range. f(x) is 1-to-1.

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