1 / 9

The Binomial Theorem

The Binomial Theorem. Connecting binomial expansion to combinations. Used in science, probability theory, game theory, statistics and combinatorics. Expand (3x – 2) 10. (3x – 2)(3x – 2)(3x – 2)(3x – 2)(3x – 2)(3x –2)(3x – 2) (3x – 2)(3x – 2)(3x – 2) = Have fun!!!

Télécharger la présentation

The Binomial Theorem

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript


  1. The Binomial Theorem Connecting binomial expansion to combinations. Used in science, probability theory, game theory, statistics and combinatorics

  2. Expand (3x – 2)10 (3x – 2)(3x – 2)(3x – 2)(3x – 2)(3x – 2)(3x –2)(3x – 2) (3x – 2)(3x – 2)(3x – 2) = Have fun!!! The binomial theorem is a method used to expand binomials raised to large powers.

  3. The Binomial Theorem: notation is just another way of writing a combination such as n C k .

  4. So to find (x + 2)5 or Notice that the exponents on each term always add up to n. Find the combination values and simplify.

  5. Back to (3x – 2)10 = Take your time and write the expansion steps out to avoid mistakes. (3x – 2)10 = 10C0 (3x)10–0(–2)0 + 10C1 (3x)10–1(–2)1 + 10C2 (3x)10–2(–2)2 + 10C3 (3x)10–3(–2)3 + 10C4 (3x)10–4(–2)4 + 10C5 (3x)10–5(–2)5 + 10C6 (3x)10–6(–2)6 + 10C7 (3x)10–7(–2)7 + 10C8 (3x)10–8(–2)8 + 10C9 (3x)10–9(–2)9 + 10C10 (3x)10–10(–2)10 =

  6. (1)(59049)x10(1) + (10)(19683)x9(–2) + (45)(6561)x8(4) + (120)(2187)x7(–8) + (210)(729)x6(16) + (252)(243)x5(–32) + (210)(81)x4(64) + (120)(27)x3(–128) + (45)(9)x2(256) + (10)(3)x(–512) + (1)(1)(1)(1024) = 59049x10 – 393660x9 + 1180980x8 – 2099520x7 + 2449440x6 – 1959552x5 + 1088640x4 – 414720x3 + 103680x2 – 15360x + 1024

  7. Practice Expand • (x2 + 3)6 x12 + 18x10 + 135x8 + 540x6 + 1215x4 + 1458x2 + 729 • (2x – 5y)7 128x7 – 2240x6y + 16800x5y2 – 70000x4y3 + 175000x3y4 – 262500x2y5 + 218750xy6 – 78125y7

  8. Finding a specific term. • Notice that every expansion has one more term than the original exponent on the binomial. • If you are asked to find the 5th term of (x – 3)9 the k value will be 5 – 1= 4 so: the 5th term would be 9C4x9-4(-3)4 =126x5(81) = 10206x5

  9. Find: • the tenth term in the expansion of (x + 3)12 4330260x3 • Find the 5th term of (3x – 4)12 831,409,920x8

More Related