170 likes | 417 Vues
SAS. Subtraction. 180. 270. Chapter 7 Section 7.3. Rotations. PQR is Rotated about point P to form PQ’R’ P is the center of rotation QPQ’ or RPR’ is the angle of rotation. Theorem 7.2 Rotation Theorem A rotation is an isometry.
E N D
SAS Subtraction 180 270
Chapter 7Section 7.3 Rotations
PQR is Rotated about point P to form PQ’R’ P is the center of rotation QPQ’ or RPR’ is the angle of rotation Theorem 7.2Rotation Theorem A rotation is an isometry
A 120º rotation of an equilateral triangle shows that it has rotational symmetry
45° Clockwise Rotation 90° Clockwise Rotation Yes the figure has rotational symmetry a 90° rotation
45° Clockwise Rotation 90° Clockwise Rotation 120° Clockwise Rotation Yes the figure has rotational symmetry a 120° rotation
45° Clockwise Rotation Yes the figure has rotational symmetry a 45° rotation
45° Clockwise Rotation Yes the figure has rotational symmetry a 45° rotation
HPA GPH
Theorem P ABC A’B’C’ by a reflection over m A’B’C’ A”B”C” by a reflection over k ABC A”B”C” by a rotation around P
Theorem 7.3 Continued P ABC A”B”C” by a rotation around P Angle of rotation = 2(40) = 80
Angle of Rotation = 2(32) = 64 Angle of Rotation = 2x = 128 x = 64
Rotate your paper the given rotation and read off the points like you did not rotate it. A(1, 3) B(3, 3) C(3, -1) D(1, -1)
Rotate your paper the given rotation and read off the points like you did not rotate it. A(2, 0) B(3, -2) C(2, -4) D(1, -2)
Rotate your paper the given rotation and read off the points like you did not rotate it. A(-2, 0) B(-4, 1) C(-4, 5) D(-2, 4)