1 / 9

Ex. 1 Solve by factoring. 2x 2 + 9x + 7 = 0 6x 2 – 3x = 0

Ex. 1 Solve by factoring. 2x 2 + 9x + 7 = 0 6x 2 – 3x = 0. (2x + 1)(x + 4) = 0. 2x + 1 = 0 x + 4 = 0. x = - ½ x = - 4. 3x(2x – 1) = 0. 3x = 0 2x – 1 = 0. x = 0 x = ½. Ex. 2 Solve by extracting square roots. A. 4x 2 = 12.

zacharylong
Télécharger la présentation

Ex. 1 Solve by factoring. 2x 2 + 9x + 7 = 0 6x 2 – 3x = 0

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript


  1. Ex. 1 Solve by factoring. 2x2 + 9x + 7 = 0 6x2 – 3x = 0 (2x + 1)(x + 4) = 0 2x + 1 = 0 x + 4 = 0 x = - ½ x = - 4 3x(2x – 1) = 0 3x = 0 2x – 1 = 0 x = 0 x = ½

  2. Ex. 2 Solve by extracting square roots A. 4x2 = 12 B. (x - 2)2 = 5 x2 = 3 Ex. 3 Completing the Square x2 - 6x + 2 = 0 First, take 2 to the other side. x2 - 6x = -2 To complete the square take half the x-term and square it. Add it to both sides. x2 - 6x = -2 + 9 + 9 (x - 3)2 = 7

  3. Ex. 4 Completing the Square when the leading coefficient is not 1 Divide each term by 3. Take 5/3 to the other side. Now, complete the square. Take the square root of both sides.

  4. Ex. 7 Use the Quadratic Formula to solve x2 + 3x - 9 = 0

  5. Ex. 8 Solve by factoring. x4 - 3x2 + 2 = 0 Factor Set both factors = 0 or factor again. (x2 - 2)(x2 - 1) = 0 x2 - 2 = 0 x2 = 2 x2 - 1 = 0 x2 = 1

  6. Ex. 9 Solve by grouping. x3 - 3x2 - 3x + 9 = 0 x2(x - 3) - 3(x - 3) = 0 Factor out an (x - 3) (x - 3)(x2 - 3) = 0 x = 3

  7. Ex. 10 Solving a Radical Isolate the radical. Now square both sides. 2x + 7 = x2 + 4x + 4 0 = x2 + 2x - 3 Factor or use quad. formula 0 = (x + 3)(x - 1) Possible answers for x are - 3 and 1. Check them in the original equation to see if they work. Only x = 1 works!

  8. Ex. 11 An equation Involving Two Radicals Isolate the more complicated rad. Square both sides. Once again, isolate the radical. Square both sides. x2 + 2x + 1 = 4(x + 4) (x - 5)(x + 3) = 0 x2 - 2x - 15 = 0 Only x = 5 works.

  9. Ex. 12 Solving an Equation Involving Absolute Value Split into 2 equations. x2 - 3x = -4x + 6 x2 - 3x = 4x -6 Now solve them for x. x2 + x - 6 = 0 x2 - 7x + 6 = 0 (x + 3)(x - 2) = 0 (x - 1)(x - 6) = 0 Possible answers are -3, 2, 1, and 6. Which ones work? -3 and 1

More Related